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pickupchik [31]
3 years ago
9

Which of the following atoms has six valence electrons? (2 points)

Chemistry
1 answer:
irakobra [83]3 years ago
4 0

The correct answer is Sulfur (S).


Sulfur has 6 valence electrons because it is located in Group 16 (or the sixth group over if you don’t count the transition metals). This means that one atom of sulfur has 6 electrons in its outermost shell out of 8 total “spots”, which you can count by counting the group numbers (excluding the transition metals) from Group 1 (with one valence electron) to Group 18 (the noble gases with full valence or outer shells).


By this same logic, Carbon (C) has 4 valence electrons and Cesium (Cs) has 1 valence electron, so neither of these is the correct answer.


Hope this helps!

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3 years ago
Can someone please help I need help?!?!
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Answer:

a: 6 moles

b: 6.75 moles

c: 5 grams

Explanation:

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7 0
3 years ago
What is the limiting reagent when a 2.00 g sample of ammonia is mixed with 4.00 g of oxygen?​
UNO [17]

Answer:

Ammonia is limiting reactant

Amount of oxygen left  = 0.035 mol

Explanation:

Masa of ammonia = 2.00 g

Mass of oxygen = 4.00 g

Which is limiting reactant = ?

Balance chemical equation:

4NH₃ + 3O₂     →     2N₂ + 6H₂O

Number of moles of ammonia:

Number of moles = mass/molar mass

Number of moles = 2.00 g/ 17 g/mol

Number of moles = 0.12 mol

Number of moles of oxygen:

Number of moles = mass/molar mass

Number of moles = 4.00 g/ 32 g/mol

Number of moles = 0.125 mol

Now we will compare the moles of ammonia and oxygen with water and nitrogen.

                      NH₃          :            N₂

                        4             :             2

                      0.12           :           2/4×0.12 = 0.06

                      NH₃         :            H₂O

                        4            :             6

                        0.12       :           6/4×0.12 = 0.18

                       

                       O₂            :            N₂

                        3             :             2

                      0.125        :           2/3×0.125 = 0.08

                        O₂           :            H₂O

                        3              :             6

                        0.125       :           6/3×0.125 = 0.25

The number of moles of water and nitrogen formed by ammonia are less thus ammonia will be limiting reactant.

Amount of oxygen left:

                        NH₃          :             O₂

                           4            :              3

                           0.12       :          3/4×0.12= 0.09

Amount of oxygen react = 0.09 mol

Amount of oxygen left  = 0.125 - 0.09 = 0.035 mol

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