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3 years ago

4) What mass of hydrogen is formed when 2.00g of magnesium Mg + H2SO4–>H2SO4

Chemistry

2 answers:

svet-max [94.6K]3 years ago

8 0

Answer: 0.16 g H2

Explanation:

Mg+ H2SO4= MgSO4 + H2

Atomic massof Mg is 24

Molecular mass of H2 is 2

So,

24g Mg produce 2 g H2

1g Mg produce (2÷24)= 0.083 g H2

2.00g Mg produce (0.083×2) g H2

= 0.16 g H2

0.16g of hydrogen is formed when 2.00g of magnesium.

DochEvi [55]3 years ago

7 0

Answer:

0.16g

Explanation:

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Answer:

only chlorine can expand its octet.

Explanation:

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3 years ago

Ne4ueva [31]

Answer:

32,127.02 grams of hydrogen hexafluorosilicate will contain this 25,434 grams of F.

Explanation:

Volume of cylindrical reservoir = V

Radius of the cylindrical reservoir = r = d/2

d = diameter of the cylindrical reservoir = d = $4.50\times 10^1 m=45 m$

r = d/2 = 22.5 m

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Mass of water cylindrical reservoir = m

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1.6 kilogram of fluorine per million kilograms of water. (Given)

Concentration of fluorine in water = 1.6 kg/ 1000,000 kg of water

In 1000,000 kg of water = 1.6 kg of fluorine

Then $15,896,250 kg$ of water have x mass of fluorine:

$\frac{x}{15,896,250 kg\text{kg of water}}=\frac{1.6 kg}{1000,000 \text{kg of water}}$

$x=\frac{1.6 kg}{1000,000}\times 15,896,250 kg=25.434 kg$

15,896,250 kg water of contains mass 25.434 kg of fluorine.

25.434 kg = 25434 g

25,434 grams of fluorine should be added to give 1.6 ppm.

Percentage of fluorine in hydrogen hexafluorosilicate :

Molar mass hydrogen hexafluorosilicate = 144 g/mol

$F\%=\frac{6\times 19 g/mol}{144 g/mol}\times 100=79.16\%$

Total mass of hydrogen hexafluorosilicate = m'

$79.16\%=\frac{25,434 g}{m'}\times 100$

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32,127.02 grams of hydrogen hexafluorosilicate will contain this 25,434 grams of F.

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3 years ago

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Answer:

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Explanation:

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