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3 years ago

Why is it important for DNA to be duplicated before mitosis

1 answer:

7 0

<span>If it didn't, one cell would end up with the original DNA, the other wouldn't be a functional cell, because it would lack DNA. If the DNA was split between the two cells.</span>

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An object is found to have a mass of 54.3 g. Find the object’s density, if its volume is 47.18 cm3

Schach [20]

Answer:

d≈ 1.15 g/cm^3

Explanation:

The density of an object can be found by dividing the mass over the volume.

d= m/v

The mass of the object is 54.3 grams and the volume is 47.18 cubic centimeters.

m= 54.3 g

v= 47.18 cm^3

Substitute the values into the formula.

d= 54.3 g/ 47.18 cm

Divide.

d= 1.150911403136922 g/cm^3

Let’s round to the nearest hundredth. The 0 in the thousandth place tells us to leave the 5 in the hundredth place.

d ≈ 1.15 g/cm^3

The density is about 1.15 grams per cubic centimeter.

8 0

3 years ago

The molar mass of cadnium chloride is 183 g. If 300 mL of a solution contains 18.3 g CdCl2, the molarity of the solution is:

zavuch27 [327]

Answer:

E. (None of these).

It is 0.333 M.

Explanation:

A molar solution would contain 183 g in 1 liter.

By proportion, this solution contains 18.3 * 1000/300

= 61 g per liter.

So it is 61 / 183 = 0.333 M.

6 0

3 years ago

A major difference between deep ocean currents and surface currents is that deep ocean currents _____.

Andrew [12]

The correct answer is c

8 0

3 years ago

Read 2 more answers

Dolomite is a mixed carbonate of calcium and magnesium. Calcium and magnesium carbonates both decompose upon heating to produce

Setler79 [48]

Answer:

72.03 %

Explanation:

Total mass of dolomite = 9.66 g

Let the mass of Magnesium carbonate = x g

The mass of calcium carbonate = 9.66 - x g

Calculation of the moles of Magnesium carbonate as:-

Molar mass of Magnesium carbonate = 122.44 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{x\ g}{84.3139\ g/mol}=\frac{x}{84.3139}\ mol$

Calculation of the moles of calcium carbonate as:-

Molar mass of calcium carbonate = 100.0869 g/mol

Thus,

$Moles= \frac{9.66 - x\ g}{100.0869\ g/mol}=\frac{9.66 - x}{100.0869}\ mol$

According to the reaction shown below:-

$MgCO_3\rightarrow MgO+CO_2$

$CaCO_3\rightarrow CaO+CO_2$

In both the cases, the oxides formed from the carbonates in the 1:1 ratio.

So, Moles of MgO = $\frac{x}{84.3139}\ mol$

Molar mass of MgO = 40.3044 g/mol

Thus, Mass = Moles*Molar mass = $\frac{x}{84.3139}\times 40.3044 \ g$

Moles of CaO = $\frac{9.66 - x}{100.0869}\ mol$

Molar mass of CaO = 56.0774 g/mol

Thus, Mass = Moles*Molar mass = $\frac{9.66 - x}{100.0869}\times 56.0774 \ g$

Given that total mass of the oxide = 4.84 g

Thus,

$\frac{x}{84.3139}\times 40.3044 +\frac{9.66 - x}{100.0869}\times 56.0774=4.84$

$\frac{40.3044x}{84.3139}+56.0774\times \frac{-x+9.66}{100.0869}=4.84$

$-694.1618435x+45673.48749\dots =40843.38968\dots$

$x=\frac{4830.09780\dots }{694.1618435}$

$x=6.9582$

Thus, the mass of Magnesium carbonate = 6.9582 g

$\%\ mass=\frac{Mass_{MgCO_3}}{Total\ mass}\times 100$

$\%\ mass=\frac{6.9582}{9.66}\times 100=72.03\ \%$

3 0

3 years ago

A typical adult human body contains approximately 2.500 L of blood plasma. How many grams of blood plasma are in the typical adu

kirill115 [55]

Answer:

$m=2.575g$

Explanation:

Hello,

In this case, since the density is defined as the ratio of the mass and volume:

$\rho =\frac{m}{V}$

We can compute the mass of blood as follows:

$m=\rho *V=1.03g/L*2.500L\\\\m=2.575g$

Best regards.

7 0

3 years ago