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tatyana61 [14]
3 years ago
11

Determine the mass of chloride (mw = 35.45 g/mol ) in grams present in 100 ml of a 0.325 m solution of aqueous ticl3 (titanium(i

ii) chloride).
Chemistry
1 answer:
Lana71 [14]3 years ago
4 0

 The  mass   chloride is  3.456 grams


 calculation

 Step:1 calculate the moles of TiCl3

moles = molarity  x  volume  in liters

volume in liters = 100 ml /1000 =  0.1 L

molarity = 0.325  M  =  0.325  mol / L

moles  is therefore  =  0.1 L x  0.325  mol /L = 0.0325   moles

step 2: find the moles of Cl

since there is  3  atoms of  cl in TiCl3  the moles of Cl

= 3 x 0.0325 =0.0975 moles


Step 3:  calculate  mass  of cl

 mass= moles  x molar mass

=0.0975 moles x 35.45 g/mol = 3.456 g




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Mass of benzene = 7.35 g

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Heat fusion of benzene,\Delta H_{fus} = 9.92 kJ/mol

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Q=\Delta H_{fus}\times 0.09423 mol

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(1 kJ = 1000 J)

2) Heat vaporization of benzene,\Delta H_{vap} = 30.7 kJ/mol

Heat required to vaporize 7.35 g of benzene at its normal melting point = Q

Q=\Delta H_{Vap}\times 0.09423 mol

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4 years ago
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Next, we shall determine the masses of Na and O2 that reacted from the balanced equation.

This is illustrated below:

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From the balanced equation above,

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Finally, we shall determine the mass of O2 needed to react with 18 g of Na.

This can be obtain as follow:

From the balanced equation above,

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