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Nesterboy [21]
3 years ago
7

Why do you suppose the structural polysaccharide cellulose does not contain branches? Why do you suppose the structural polysacc

haride cellulose does not contain branches? Branches in the molecule would generate side chains that would almost certainly make it difficult to pack the cellulose molecules into globules, thereby decreasing the flexibility and strength of the globules. Branches in the molecule would generate side chains that would almost certainly make it difficult to pack the cellulose molecules into microfibrils, thereby increasing the rigidity and strength of the microfibrils. Branches in the molecule would generate side chains that would almost certainly make it difficult to pack the cellulose molecules into globules, thereby increasing the flexibility and strength of the globules. Branches in the molecule would generate side chains that would almost certainly make it difficult to pack the cellulose molecules into microfibrils, thereby decreasing the rigidity and strength of the microfibrils.
Chemistry
1 answer:
madam [21]3 years ago
3 0

The correct statement is that branches in the molecule would generate side chains that would almost certainly make it difficult to pack the cellulose molecules into microfibrils, thereby decreasing the rigidity and strength of the microfibrils.

The prime polysaccharide found in the plants, which is responsible for the structural role is cellulose. It is one of the most naturally abundant organic constituents found on Earth. It is an unbranched polymer of glucose residues, which is combined together through beta-1,4 linkages that permit the molecules to produce straight and long chains. The cellulose molecules are linear, rigid rods, which combines laterally into microfibrils.  


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Hydrogen gas and oxygen gas react to form liquid water according to the following equation:

2H₂ + O₂ → 2H₂O

a. Converting our given masses of each gas to moles, we have:

(25 g H2)/(2 × 1.008 g/mol) = 12.4 mol H2; and

(25 g O2)/(2 × 15.999 g/mol) = 0.781 mol O2.

From the equation, two moles of H2 react with every one mole of O2. To fully react with 12.4 moles of H2, as we have here, one would need 6.2 moles of O2, which is far more than what we're actually given. Thus, the oxygen is our limiting reactant, and as such it will be the first reactant to run out.

b. Since O2 is our limiting reactant, we use it for determining how much product, in this case, H2O, is produced. From the equation, there is a 1:1 molar ratio between O2 and H2O. Thus, the number of moles of H2O produced will be the same as the number of moles of O2 that react: 0.781 moles of H2O. The mass of water produced would be (0.781 mol H2O)(18.015 g/mol) ≈ 14 grams of water (the answer is given to two significant figures).

c. Since the hydrogen reacts with the oxygen in a 2:1 ratio, twice the number of moles of oxygen in hydrogen is consumed: 0.781 mol O2 × 2 = 1.562 mol H2. Since we began with 12.4 moles of H2, the remaining amount of excess H2 would be 12.4 - 1.562 = 10.838 mol H2. The mass of the excess hydrogen reactant would thus be (10.838 mol H2)(2 × 1.008 g/mol) ≈ 22 grams of hydrogen gas (the answer is given to two significant figures).

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3 years ago
The gravitational force of Earth is causing volcanoes on the moon. True or false?
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The first five questions refer to the following problem:
MariettaO [177]

The Acceleration of a model rocket = 4 m/s²

<h3>Further explanation  </h3>

Newton's 2nd law explains that the acceleration produced by the resultant force on an object is proportional and in line with the resultant force and inversely proportional to the mass of the object  

∑F = m. a  

\large{\boxed{\bold{a=\frac{\sum F}{m}}}

F = force, N  

m = mass = kg  

a = acceleration due to gravity, m / s²  

An upward thrust of 35 N

A model rocket has a mass of 2.5 kg(weight = 25 N)

so resultant force :

\tt \sum F=F~upward~thrust-F~weight\\\\\sum F=35-25\\\\\sum F=10~N

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