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Digiron [165]
3 years ago
9

The following equation shows the equilibrium in an aqueous solution of ammonia:NH3(aq)+H2O(l)⇌NH4+(aq)+OH−(aq)Which of the follo

wing represents a conjugate acid-base pair?NH3 and H2ONH4+ and OH−H2O and OH−NH3 and
Chemistry
1 answer:
victus00 [196]3 years ago
4 0

Answer:

OH⁻ and H₂O

Explanation:

From the equation given in question ,

NH₃ (aq) + H₂O (l) ⇌ NH₄⁺ (aq) + OH⁻ (aq)

Acids are the species which furnish hydrogen ions in the solution or is capable of forming bonds with electron pair species as they are electron deficient species.

When an acid donates a proton, it changes into a base which is known as its conjugate base.

Bases are the species which furnish hydroxide ions in the solution or is capable of forming bonds with electron deficient species as they are electron rich species. When a base accepts a proton, it changes into a acid which is known as its conjugate acid.

The acid and the base which is only differ by absence or presence of the proton are known as acid conjugate base pair.

Hence , from the equation given in the question ,

The conjugate acid - base pair is -

OH⁻ and H₂O

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Answer:

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Explanation:

For N2,

                Pressure(P₁)=125 kPa

                  Volume(V₁)=15·1 L

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Similarly, for Oxygen,

                   Pressure(P₂)= 125 kPa

                   Volume(V₂)= 44.3 L

                  Temperature(T₂)=25°C= 298 K

Then, for the mixture,

              Volumeof the mixture( V)= 6.25 L

                                     Pressure(P)=?

                Temperature (T)= 51°C = 51+273 K=324 K

Then, By Combined gas laws,

                                 \frac{P_{1} V_{1} }{T_{1} } +\frac{P_{2} V_{2} }{T_{2} } =\frac{PV}{T}

                      or, \frac{15.1*125}{298} +\frac{44.3*125}{298} =\frac{P*6.25}{324}

                     or, 6.34+18.58=\frac{P*6.25}{324}

                     or, P=\frac{24.92*324}{6.25}

                        ∴P=1291.85 kPa

So the total pressure of the mixture in the tank of volume 6.25 litres at 51°C  is 1291.85 kPa.

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