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Digiron [165]
3 years ago
9

The following equation shows the equilibrium in an aqueous solution of ammonia:NH3(aq)+H2O(l)⇌NH4+(aq)+OH−(aq)Which of the follo

wing represents a conjugate acid-base pair?NH3 and H2ONH4+ and OH−H2O and OH−NH3 and
Chemistry
1 answer:
victus00 [196]3 years ago
4 0

Answer:

OH⁻ and H₂O

Explanation:

From the equation given in question ,

NH₃ (aq) + H₂O (l) ⇌ NH₄⁺ (aq) + OH⁻ (aq)

Acids are the species which furnish hydrogen ions in the solution or is capable of forming bonds with electron pair species as they are electron deficient species.

When an acid donates a proton, it changes into a base which is known as its conjugate base.

Bases are the species which furnish hydroxide ions in the solution or is capable of forming bonds with electron deficient species as they are electron rich species. When a base accepts a proton, it changes into a acid which is known as its conjugate acid.

The acid and the base which is only differ by absence or presence of the proton are known as acid conjugate base pair.

Hence , from the equation given in the question ,

The conjugate acid - base pair is -

OH⁻ and H₂O

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How can you tell one elements from another?
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WILL GIVE BRAINLIEST <br> Explain why HS2 has a bent geometry, while BeH2 has a linear geometry.
Natali5045456 [20]

Answer:

H2S has a bent geometry, while BeH2 has a linear geometry because: presence of lone pair in H2S

Absence of Lone pair in BeH2

Explanation:

<u>Structure of H2S :</u>

Atomic number of S = 16 = 1s(2 )2s(2) 2p(6) <u>3s(2 )3p(4)</u>

Outer most shell has 6 electron

Valence electron (Involved in bonding) = 6

Out of these  6 electrons ,

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There are 2-Lone pair on S in H2S (look at the image attached)

<u>Structure of H2S :</u>

Atomic number of Be = 4 = 1s(2 ) 2s(2)

Valence electron (Involved in bonding) = 2

These 2- electron  are involved in bonding with two Hydrogen and form liner shape.*Form sp - hybridized

Hence shape is linear because it has non - lone pair.

VSEPR : <u><em>According to this theory lone pair causes repulsion to the bond and cause unstability in the molecule.</em></u>

<u><em>Hence the bonds shifts away from lone pairs . This is why H-S bonds in H2S  shifts way from lone pair</em></u>

5 0
3 years ago
50 POINTS!!!! Please Help I'm being timed and this would help so much! 50 POINTS!!!!
Studentka2010 [4]

Answer:

[H⁺] = 1.0 x 10⁻¹² M.

Explanation:

∵ [H⁺][OH⁻] = 10⁻¹⁴.

[OH⁻] = 1 x 10⁻² mol/L.

∴ [H⁺] =  10⁻¹⁴/[OH⁻] = (10⁻¹⁴)/(1 x 10⁻² mol/L) = 1.0 x 10⁻¹² M.

∵ pH = - log[H⁺] = - log(1.0 x 10⁻¹² M) = 12.0.

∴ The solution is basic, since pH id higher than 7 and also the  [OH⁻] > [H⁺].

I think- IDK

5 0
3 years ago
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