A line in the xy-plane with the slope -4/5 passes through the point (3,4). Which of the following points lies on the line?

Mathematics

1 answer:

Rama09 [41]3 years ago

6 0

Answer:

(9,3)

Step-by-step explanation:

I don't think any of the answer choices are correct 9/3 is

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Find the additive inverse of 7/10

11111nata11111 [884]

$\huge\fbox{Hi~there!}$

Remember, a number's additive inverse is simply its opposite.

Let's say we have a number a.

The opposite of a is -a, and the opposite of -a is a.

Thus, the additive inverse of

$\displaystyle\frac{7}{10}$ is

$\displaystyle-\frac{7}{10}$

Hope it helps.

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3 years ago

Add (2x + 2) and (4x – 7)

natta225 [31]

The right answer is 6x + 5

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Given that 1 x2 dx 0 = 1 3 , use this fact and the properties of integrals to evaluate 1 (4 − 6x2) dx. 0

Debora [2.8K]

So, the definite integral $\int\limits^1_0 {(4 - 6x^{2} )} \, dx= - 74$

Given that

$\int\limits^1_0 {x^{2} } \, dx = 13$

We find

$\int\limits^1_0 {(4 - 6x^{2} )} \, dx$

<h3>Definite integrals </h3>

Definite integrals are integral values that are obtained by integrating a function between two values.

So, $Integral \int\limits^1_0 {(4 - 6x^{2} )} \, dx$

So, $\int\limits^1_0 {(4 - 6x^{2} )} \, dx = \int\limits^1_0 {4} \, dx - \int\limits^1_0 {6x^{2} } \, dx \\= 4[x]^{1}_{0} - \int\limits^1_0 {6x^{2} } \, dx \\= 4[x]^{1}_{0} - 6\int\limits^1_0 {x^{2} } \, dx \\= 4[1 - 0] - 6\int\limits^1_0 {x^{2} } \, dx\\= 4[1] - 6\int\limits^1_0 {x^{2} } \, dx\\= 4 - 6\int\limits^1_0 {x^{2} } \, dx$