Answer:
<h2>Hereis the correct answer </h2>
(A. Au3+ and CI2)
Explanation:
<h3>STUDY CORRECTION. </h3>
Answer:
Explanation:
Hello,
In this case, the undergoing chemical reaction is:
Thus, we proceed to compute the reacting moles of Pb(NO3)2 and KI, by using the given concentrations and densities and molar masses which are 331.2 g/mol and 166 g/mol respectively:
Next, the 0.0464 moles of Pb(NO3)2 will consume the following moles of KI (consider their 1:2 molar ratio):
Hence, as only 0.0789 moles of KI are available, KI is the limiting reactant, therefore the formed grams of PbI2, considering its molar mass of 461.01 g/mol and 2:1 molar ratio, are:
Best regards.
Answer:
The correct answer is option C.
Explanation:
Half life for second order kinetics is given by:
= half life = 15.4 s
k = rate constant =?
= initial concentration = 0.67 M
is the rate constant for this reaction.
The missing data is the value of I.E and E.A for Cl and F, which are, Cl: I.E =1255 kJ/mol, E.A = -348.7 kJ/mol, F: I.E = 1678 kJ/mol, E.A = -327.8 kJ/mol.
Answer:
3.2
Explanation:
The electronegativity is the capacity of an atom to attract an electron in a bond. As higher is it, as higher the electron will be attracted. The ionization energy is the minimum energy necessary to remove one electron of the atom, transforming it on a cation. On the other hand, the electron affinity is the energy that is lost when the atom gains an electron and is transformed on an anion.
Calling the constant as K, and knowing that the electronegative of fluorine (F) is 4.0:
4 = K*(1678 - (-327.8))
2005.8K = 4
K = 2.00x10⁻³ mol/kJ
Thus, for chlorine (Cl):
Electronegativity = 2.00x10⁻³*(1255 - (-348.7))
Electronegativity = 3.2
