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Vedmedyk [2.9K]
4 years ago
5

Which radioisotopes have the same decay mode and have half-lives greater than

Chemistry
2 answers:
Damm [24]4 years ago
5 0
The answer is (3) I-131 and P-32. They both have β- decay mode and with half-lives greater than hour. You can get these half-lives and decay mode from table N selected radioisotopes.
AveGali [126]4 years ago
4 0

The correct answer is (3)


I-131 and P-32


The explanation:


according to attached table:


- we can see that the half life of p 32 is 14.28d (more than one hour)

- and the half life of I-131 is 8.021 d (more than one hour)


and They both have β- decay mode and with half-lives greater than hour.


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Find the mass, in grams, of 5.00*10^23 molecules of F2
Westkost [7]

Answer:   31.55 g

Explanation:

- The mass number of Fluoride atom (F) = 18.99 g/mol, so mass number of         fluorine gas (F2) = 37.98 g/mol.

-  1 mole of (F2) [which has 37.98 g/mol] contains Avogadro’s number of molecules (6.02×10^23 molecules),

   so   1 mole of (F2) with 37.98 g/mol →  6.02×10^23 molecules.

- Using cross multiplication,  

                               37.98 g/mol of (F2)        →       6.02 ×10^23 molecules

                                                       ?              →        5.00 ×10^23 molecules

Hence the mass of 5.00×10^23 molecules of F2 = (37.98 × 5.00 × 10^23) / 6.02 ×10^23 = 31.55 g..


7 0
4 years ago
The common titanium alloy known as T-64 has a composition of 90 weight% titanium 6 wt% aluminum and 4 wt% vanadium. Calculate th
Anna007 [38]

Explanation:

Suppose in 100 g of alloy contains 90% titanium 6% aluminum and 4% vanadium.

Mass of titanium = 90 g

Moles of titanium = \frac{90 g}{47.87 g/mol}=1.8800 mol

Total number of atoms of titanium ,a_t=1.8800 mol\times N_A

Mass of aluminum = 6 g

Moles of aluminium = \frac{6 g}{26.98 g/mol}=0.2223 mol

Total number of atoms of aluminium,a_a=0.2223 mol\times N_A

Mass of vanadium  = 4 g

Moles of vanadium= \frac{4 g}{50.94 g/mol}=0.0785 mol

Total number of atoms of vanadiuma_v=0.0785 mol\times N_A

Total number of atoms in an alloy = a_t+a_a+a_v

Atomic percentage:

Atomic\%=\frac{\text{total atoms of element}}{\text{Total atoms in alloy}}\times 100

Atomic percentage of titanium:

:\frac{a_t}{a_t+a_a+a_v}\times 100=\frac{1.8800 mol\times N_A}{1.8800 mol\times N_A+0.2223 mol\times N_A+0.0785 mol\times N_A}\times 100=86.20\%

Atomic percentage of Aluminium:

:\frac{a_a}{a_t+a_a+a_v}\times 100=\frac{0.2223 mol\times N_A}{1.8800 mol\times N_A+0.2223 mol\times N_A+0.0785 mol\times N_A}\times 100=10.19\%

Atomic percentage of vanadium

:\frac{a_v}{a_t+a_a+a_v}\times 100=\frac{0.0785 mol\times N_A}{1.8800 mol\times N_A+0.2223 mol\times N_A+0.0785 mol\times N_A}\times 100=3.59\%

6 0
4 years ago
Hydrocarbons, compounds containing only carbon and hydrogen, are important in fuels. The heat of combustion of cyclopentane, C5H
pishuonlain [190]

Answer:

4664.54  kcal of energy is produced on the complete combustion of 416 grams of cyclopentane

Explanation:

Combustion is the process by which hydrocarbons react with oxygen to heat to produce heat energy.

The heat energy produced when one mole of an hydrocarbon is completely burnt or combusted in air is called the heat of combustion

The balanced equation for the complete combustion of cyclopentane (C5H10) is given below:

             2C₅H₁₀ + 15O₂ → 10CO₂ + 10H₂O

                                                             ΔH combustion = 786.6 kcal/mol

What the above equation means is that each time one mole of cyclopentane is completely burnt, 786.6kcal of energy is released.

Hence we need to calculate the number of moles of cyclopentane in 416grams; therefore

No of moles cyclopentane = mass of cyclopentane / molar mass of cycopentane  

                                             = 416 g / 70.1 g/mol

                                             = 5.9343moles

                                             ≅ 5.93 moles of cyclopentane in 416grams

From the question, since the  cyclopentane is completely combusted, it implies that the energy released would be

    1 mole of cyclopentane     = 786.6 kcal of energy

   5.93 moles of cyclopentane would produce    

                                                = 5.93 moles x 786.6kcal/mol

                                                = 4664.54  kcal of energy

6 0
3 years ago
33 grams of NH4NO3 will produce how many grams of water
Leni [432]

Answer:

66 grams

Explanation:

For every 1 gram of NH4NO3 equals 2 grams of water

8 0
4 years ago
Define What is boiling
kozerog [31]

Answer:

Boiling is the rapid vaporization of a liquid, which occurs when a liquid is heated to its boiling point, the temperature at which the vapour pressure of the liquid is equal to the pressure exerted on the liquid by the surrounding atmosphere.

Explanation:

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8 0
3 years ago
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