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3 years ago

Can someone please help me, best answer gets BRAINLIEST

Chemistry

1 answer:

salantis [7]3 years ago

7 0

Answer:

9839 is your answer mate .

Plz mark brainliest and follow me ❤❤❤❤

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An element has 8 protons and 8 neutrons in its nucleus and 8 electrons revolving around the nucleus. What is the atomic number a

ExtremeBDS [4]

The mass of an atom comes from the protons and neutrons that are found in the nucleus. The number of protons is the atomic number of an element. To find the number of neutrons, subtract the atomic number from the mass of an atom. The atomic number is 8 and the atomic mass is 16.

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3 years ago

ASAP!<br> I have 20 min to finish this i need help

rodikova [14]

The real answer is B

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3 years ago

Put an x of it is a physical property but of it is a chemical propety pit a +

makkiz [27]

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3 years ago

If you start with 227.8 grams of iron and 128 grams of oxygen to produce iron oxide, what is the limiting reagent?

agasfer [191]

The balanced chemical equation between iron and oxygen to produce iron (III) oxide is,

$4Fe(s) + 3O_{2}(g) ---> 2Fe_{2}O_{3}(s)$

Mass of Fe = 227.8 g

Moles of Fe = $227.8 g Fe * \frac{1 mol Fe}{55.85 g Fe} = 4.079 mol Fe$

Mass of oxygen = 128 g

Moles of $O_{2} = 128 g O_{2}*\frac{1 mol O_{2}}{32 g O_{2}}= 4mol O_{2}$

Calculating the limiting reactant: The reactant that produces the least amount of product will be the limiting reactant.

Mass of iron (III) oxide produced from Iron = $4.079 mol Fe * \frac{2 mol Fe_{2}O_{3}}{4 mol Fe} *\frac{159.69 g Fe_{2}O_{3}}{1 mol Fe_{2}O_{3}} = 325.7 g Fe_{2}O_{3}$

Mass of iron (III) oxide produced from oxygen= $4 mol O_{2}*\frac{2 molFe_{2}O_{3}}{3 mol O_{2}}*\frac{159.69 g Fe_{2}O_{3}}{1 mol Fe_{2}O_{3}} = 425.84 g Fe_{2}O_{3}$

Iron (Fe) produces the least amount of the product iron (III) oxide. So, Fe is the limiting reactant.

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3 years ago

There are several ways to model a compound. One type

mr Goodwill [35]

Answer:

C4H9O2

Explanation:

there are 4 carbons, 9 hydrogens and 2 oxygens

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3 years ago