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3 years ago

How many atoms of nitrogen are in 10g of NH4NO3

1 answer:

5 0

There are 1.50 x10^6 atoms of nitrogen in 10 grams of NH4NO3. You convert the grams to moles first and then using the definition of a mole you determine the number of molecules.

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We can also use the activity series to predict reactions between a metal and an acid. what are the products of the reaction fe(s

andrew11 [14]

Answer;

FeSO4 (aq) + H2 (g)

Explanation;

The reaction between iron and dilute sulfuric acid gives a salt and hydrogen gas. (iron (ii) sulfate and hydrogen gas).

The equation for the reaction is;

Fe(s) + H2SO4 (aq) = FeSO4(aq) +H2(g)

8 0

3 years ago

What is the vapor pressure of a liquid at 305.03 K if its ∆Hvap = 28.9 kJ/mol and its normal boiling point is 341.88 K?

ASHA 777 [7]

<u>Answer:</u> The vapor pressure of the liquid is 0.293 atm

<u>Explanation:</u>

To calculate the vapor pressure of the liquid, we use the Clausius-Clayperon equation, which is:

$\ln(\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}[\frac{1}{T_1}-\frac{1}{T_2}]$

where,

$P_1$ = initial pressure which is the pressure at normal boiling point = 1 atm

$P_2$ = pressure of the liquid = ?

$\Delta H_{vap}$ = Heat of vaporization = 28.9 kJ/mol = 28900 J/mol (Conversion factor: 1 kJ = 1000 J)

R = Gas constant = 8.314 J/mol K

$T_1$ = initial temperature = 341.88 K

$T_2$ = final temperature = 305.03 K

Putting values in above equation, we get:

$\ln(\frac{P_2}{1})=\frac{28900J/mol}{8.314J/mol.K}[\frac{1}{341.88}-\frac{1}{305.03}]\\\\\ln P_2=-1.228atm\\\\P_2=e^{-1.228}=0.293atm$

Hence, the vapor pressure of the liquid is 0.293 atm

5 0

3 years ago

Plz help! The best answer will be marked as brainliest!

Anika [276]

Answer:

This is hilarious, every time I ignite, they feed me water, little do they know this heat will defeat, and hydrogen only makes me stronger!

Explanation:

When Hg is burning, it uses the oxygen from H2O and turns it into hydrogen gas, and that contributes to the burning.

8 0

3 years ago

Read 2 more answers

If the toxic quantity is 1.5 gg of ethylene glycol per 1000 gg of body mass, what percentage of ethylene glycol is fatal

Elina [12.6K]

Answer:

The percentage of ethylene glycol that is fatal is 0.15 %

Explanation:

If the toxic quantity of ethylene glycol in a 1kg or 1000 g body weight is 1.5 g then the percentage of ethylene glycol that is fatal is

$\frac{1.5}{1000}$ ˣ 100 = 0.15%

Hence, the percentage of ethylene glycol that is toxic for any body weight is 0.15%. This percentage is very important in various aspects of science including drug discovery and food production/processing

4 0

3 years ago

Which neutral element does the orbital diagram represent?

valentinak56 [21]

Answer:

Silicon

Explanation:

The total of electrons: 2 + 2 + 6 + 2 + 2

In neutral state: #electrons = #protons = 14

so element with atomic number of 14 is silicon

3 0

1 year ago