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ad-work [718]
3 years ago
9

What is the empirical formula of C3H6N2

Chemistry
1 answer:
Evgen [1.6K]3 years ago
4 0

Answer:

The empirical formula of the compound C₃H₆N₂ is C₃H₆N₂

Explanation:

The empirical formula of a compound is the formula of the compound given in the (smallest) whole number ratio of the elements of the compound

The empirical formula of S₂O₂ is SO

The empirical formula of C₃H₆O₃ is CH₂O

The given compound's molecular formula is C₃H₆N₂

The smallest whole number ratio of of the elements of the compound is 3:6:2, therefore, the empirical formula of the compound C₃H₆N₂ is C₃H₆N₂.

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Calculate the [OH-] and the pH of a solution with an [H+= .00083 M at 25 degrees
sesenic [268]
<h3>Answer:</h3>

1.2 × 10^-11 M

<h3>Explanation:</h3>

<u>We are given;</u>

Concentration of Hydrogen ions [H⁺] as 0.00083 M

<u>We are required to calculate the concentration of [OH⁻]</u>

We know that;

pH = - log [H⁺]

POH = -log[OH⁻]

Also, pH + pOH = 14

With the concentration of H⁺ we can calculate the pH

pH = -log 0.00083 M

    = 3.08

But; pH + pOH = 14

Therefore; pOH = 14 - pH

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                          = 10.92

But, pOH = -log[OH⁻]

Therefore; [OH] = -Antilog(pOH)

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6 0
2 years ago
What is the oxidation number of P in PF6^-
Hitman42 [59]
<span>F can only have oxidation number of -1
The overall compound has an oxidation number of -1
You have 6 Fs, so 6(-1) = -6
charge from F
 X = oxidation number of P
 x + (-6) = -1
solve for
x = +5</span>
5 0
2 years ago
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