Question

M1 = 3 kg, v1= < 10, -5, 13 > m/s m2 = 2 kg, v2= < -15, 7, -4 > m/s m3 = 3 kg, v2= < -28, 37, 25 > m/s what is total kinetic energy?

Answer 1

Answer:

Explanation:

Here, the three components of velocity of each of the masses are provided.

The net velocity of each of three masses are:

$v_{1} = \sqrt{v_{11}^{2} +v_{12}^{2} + v_{13}^{2}} = \sqrt{294} = 17.15 m/s$

Similarly,

v2 = 17.03 m/s

v3 = 52.71 m/s

Since kinetic energy is a scalar quantity, there will be no vectorial considerations involved.

$KE = \frac{1}{2}m_{1}v_{1}^{2} + \frac{1}{2}m_{2}v_{2}^{2} + \frac{1}{2}m_{3}v_{3}^{2}$

Net Kinetic Energy = 4898.72 J