(a) The reactance of the inductor is 25.46 ohms.
(b) The expression for the current through the inductor is I(t) = (6.32 A) sin(134t)
<h3>Ractance of the inductor</h3>
The reactance of the inductor is calculated as follows;
XL = ωL
where;
- ω is angular frequency
- L is 190 mH
v(t) = (161 V) sin(134t)
v(t) = V sin(ωt)
The reactance of the inductor is calculated as follows;
XL = (134) x (190 x 10⁻³)
XL = 25.46 ohms
<h3>Peak current in the circuit</h3>
I₀ = V₀/XL
I₀ = (161) / (25.46)
I₀ = 6.32 A
<h3>Expression for the current through the inductor</h3>
I(t) = (6.32 A) sin(134t)
Learn more about inductance here: brainly.com/question/16765199
Answer:
minimum number of photon is 4.05 × 
Explanation:
given data
energy = 50 keV = 50 × 
eV = 50 × × 1.602× 
J
thickness = 10^-3
contrast = 1%
to find out
number of incident photons
solution
we know here equation that is
E = n × h × ν .......................1
put here all these value
50 × = n × 6.6× 
× c/ 1× 
50 × × 1.602× = n × 6.6× ×( 3 × 
/ 1× )
solve it and find n
n = 4.05 ×
so here minimum number of photon is 4.05 ×
Answer:
the first one is D
Explanation:
so if the others u put are right the the second would be c
Answer:
Vi = 94.64 m/s
Explanation:
I order to find out the initial velocity of the object, we can use third equation of motion:
2ah = Vf² - Vi²
where,
a = acceleration = -9.8 m/s²
h = maximum height covered by object = 460 m - 3 m = 457 m
Vf = Final Velocity = 0 m/s (since, object momentarily stops at highest point)
Vi = Initial Velocity = ?
Therefore,
2(-9.8 m/s²)(457 m) = (0 m/s)² - Vi²
Vi = √8957.2 m²/s²
<u>Vi = 94.64 m/s</u>
Answer:
The average power is calculated as 735.0 W
Solution:
As per the question:
Total mass, M = 1200 kg
Counter mass of the elevator, m = 950
Distance traveled by the elevator, d = 54 m
Time taken, t = 3 min = 180 s
Now,
To calculate the average power:
First, we find the force needed for lifting the weight:
Force, F = (M - m)g = 
Now, the work done by this force:
W = Fd = 
Average power is given as:
