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Mashutka [201]
3 years ago
12

Pls help

Physics
1 answer:
Arte-miy333 [17]3 years ago
4 0

Answer:

sorry I dont now the answer bro i am so sorry xd ;'(

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When running a half marathon (13.1 miles), it took Kevin 8 minutes to run from mile marker 1 to mile marker 2, and 18 minutes to
Vsevolod [243]

Answer:

It took Kevin 26 minutes to run from markers 1 to 4

His average speed from mile markers 1 to 4 is 0.154 miles/minute

Kevin must run by average speed 0.1 miles/minute to finish the race

Explanation:

Lets explain how to solve the problem

A half marathon 13.1 miles

Kevin took 8 minutes to run from mile marker 1 to mile marker 2 and

18 minutes to run from mile marker 2 to mile marker 4

→ He took 8 minutes and 18 minutes to run from marker 1 to marker 4

→ The total time of the first 4 marker = 8 + 18 = 26 minutes

<em>It took Kevin 26 minutes to run from markers 1 to 4</em>

<em></em>

Average speed is total distance divided by total time

The average speed of Kevin as he ran from mile marker 1 to mile

marker 4 is the 4 miles divides by 26 minutes

→ Average speed = 4 ÷ 26 = \frac{2}{13} = 0.154 miles/minute

<em>His average speed from mile markers 1 to 4 is 0.154 miles/minute</em>

<em></em>

It took Kevin 71 minutes to pass mile marker 9

Kevin need to complete the race in 112 minutes, then what must

Kevin's average speed be as he travels from mile marker 9 to the

finish line?

The total distance of the race is 13.1 miles, he ran 9 miles

→ The remaining distance = 13.1 - 9 = 4.1 miles

He must run 4.1 miles to complete the race

The total time is 112 minutes, he used 71 minutes to run the first 9 miles

→ The remaining time = 112 - 71 = 41 minutes

He must finish the 4.1 miles in 41 minutes

→ His average speed for the last part of the race = 4.1 ÷ 41 = 0.1 mi/min

<em>Kevin must run by average speed 0.1 miles/minute to finish the race</em>

7 0
3 years ago
Read 2 more answers
The weight of an object is measured in air to be 7.0 N. The
Vinil7 [7]

Answer:

Buoyant force = 3.0 N

The object will not float.

Explanation:

Apparent weight of a body immersed in water is the actual weight of object minus buoyant force

Given in the question that;

Weight of object in air = 7.0 N

Apparent weight of object = 4.0 N

4.0 N = 7.0 N - Buoyant force

Buoyant force = 7.0 - 4.0 = 3.0 N

In this case, the buoyant force is less than weight of the object thus the object will sink.

5 0
3 years ago
A ray of yellow light (f = 5.09 × 1014hz) travels at a speed of 2.04 × 108meters per second in
denis23 [38]
Velocity = fλ

where f is frequency in Hz, and λ is wavelength in meters.

2.04 * 10⁸ m/s =  5.09 * 10¹⁴  Hz   *  λ

(2.04 * 10⁸ m/s) / (5.09 * 10¹⁴  Hz ) = λ

4.007*10⁻⁷  m =  λ

The wavelength of the yellow light = 4.007*10⁻⁷  m
8 0
3 years ago
Hàng ngày ta thấy Mặt trời , Mặt trăng quay quanh Trái Đất, khi đó ta đã lấy vật mốc là
marshall27 [118]
I’m sorry I don’t understand this language
5 0
3 years ago
A 2-kg toy car accelerates from 5 to 10 m/s.
andre [41]
<h3><u>Full Question:</u></h3>

A 2-kg toy car accelerates from 5 to 10 m/s in 2 seconds. Find the applied force.

<h2><u>Answer:</u></h2>

Force applied is 5\frac {kgm} {s^2}.

<h3><u>Explanation:</u></h3>

Force is defined as something which changes or tends to change the velocity of a body. And acceleration is defined as the rate of change of velocity of a body per time. Both of them are vector quantities.

The initial velocity of the body = 5 m/s.

The final velocity of the body = 10 m/s.

So the change in velocity = 10 - 5 m/s = 5m/s.

Time period = 2 seconds.

So acceleration =\frac52 m/s^2= 2.5 m/s^2

The force is defined as the product of mass and acceleration of the body.

Mass of body = 2 kg.

So, force applied =  2 \times 2.5 kgm/s^2. =5kgm/s^2.

4 0
3 years ago
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