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3 years ago

7

A race car travels a circular track at an average rate of 135 mi/hr. The radius of the track is 0.450 miles. What is the centrip

etal acceleration of the car?

2 answers:

kenny6666 [7]3 years ago

7 0

135 * 135 / 0.450 = 40,500 mi/hr2

PilotLPTM [1.2K]3 years ago

4 0

Answer : $a_c=40500\ mi/h^2$ .

Explanation :

It is given that,

Velocity of a race car, v = 135 mi/hr

Radius of the track, r = 0.45 miles

We know that the centripetal acceleration is defined as :

$a_c=\dfrac{v^2}{r}$

r is the radius of the circle.

$a_c=\dfrac{(135\ mi/hr)^2}{0.45\ mi}$

$a_c=40500\ mi/h^2$

So, the centripetal acceleration of the car is $a_c=40500\ mi/h^2$ .

Hence, this is the required solution.

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