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Digiron [165]
3 years ago
7

A race car travels a circular track at an average rate of 135 mi/hr. The radius of the track is 0.450 miles. What is the centrip

etal acceleration of the car?
Physics
2 answers:
kenny6666 [7]3 years ago
7 0
135 * 135 / 0.450 = 40,500 mi/hr2 

PilotLPTM [1.2K]3 years ago
4 0

Answer : a_c=40500\ mi/h^2.

Explanation :

It is given that,

Velocity of a race car, v = 135 mi/hr

Radius of the track, r = 0.45 miles

We know that the centripetal acceleration is defined as :

a_c=\dfrac{v^2}{r}

r is the radius of the circle.

a_c=\dfrac{(135\ mi/hr)^2}{0.45\ mi}

a_c=40500\ mi/h^2

So, the centripetal acceleration of the car is a_c=40500\ mi/h^2.

Hence, this is the required solution.

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3 years ago
Determine the magnitude of the resultant force FR=F1+F2FR=F1+F2. Assume that F1F1F_1 = 235 lblb and F2F2F_2 = 350 lb
Svetlanka [38]

Answer:

<em>585lb</em>

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4 0
3 years ago
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trasher [3.6K]

Answer: A, C and D

Explanation:

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Constructive interference is said to occur when two waves superimpose to produce a wave having larger amplitude. It occurs for the waves having phase difference of multiple of 2π. On the other hand, destructive interference occurs for the waves having phase difference  π, 3π, ..and so on.

In the given picture, the bright regions represent constructive interference where as the dark ones between them represent destructive interference. Thus, the correct letters representing constructive interference are: A, C and D.

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Answer:

The intensity I₂ of the light beam emerging from the second polarizer is zero.

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