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Digiron [165]
3 years ago
7

A race car travels a circular track at an average rate of 135 mi/hr. The radius of the track is 0.450 miles. What is the centrip

etal acceleration of the car?
Physics
2 answers:
kenny6666 [7]3 years ago
7 0
135 * 135 / 0.450 = 40,500 mi/hr2 

PilotLPTM [1.2K]3 years ago
4 0

Answer : a_c=40500\ mi/h^2.

Explanation :

It is given that,

Velocity of a race car, v = 135 mi/hr

Radius of the track, r = 0.45 miles

We know that the centripetal acceleration is defined as :

a_c=\dfrac{v^2}{r}

r is the radius of the circle.

a_c=\dfrac{(135\ mi/hr)^2}{0.45\ mi}

a_c=40500\ mi/h^2

So, the centripetal acceleration of the car is a_c=40500\ mi/h^2.

Hence, this is the required solution.

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A car is traveling at a speed of 54 km/h. Breaks are applied so as to produce a uniform acceleration of -0.5 m/s2. Find how far
Lena [83]

Explanation:

u=54 km/h

54*5/18=15 m/s

v=0m/s

t=?

acceleration=-0.5m/s^2

we know that a=v-u/t

so,

t=v-u/a

t=15-0/0.5

=15/0.5

=30

therefore, the time is 30 second

Hope this answer helps you..

8 0
3 years ago
A 3.0-kg block moves up a 40o incline with constant speed under the action of a 26-N force acting up and parallel to the incline
CaHeK987 [17]

Answer:

it is very hard question for me sorry i cant solve it

3 0
3 years ago
One horse is pulling a 755 kg sled straight ahead applying a force of 1988 N. If the acceleration of the sled is 1.36 m/s2, what
Inessa [10]

Answer:

The coefficient of kinetic friction is 0.13

Explanation:

Newton's second law states that the acceleration of an object is proportional to the net force on it, the factor of proportionality is the mass. So, we can express that law mathematically as:

\sum\overrightarrow{F}=m\overrightarrow{a} (1)

With F the net force, m the mass and a the acceleration of the object. In our case we're interested on what's happening to the sled, then we have to analyze the forces on it, those forces are the weight and the normal force on the vertical direction and the pulling force and frictional force in the horizontal direction. So, because (1) is a vector equation we can express that in their vertical (y) and horizontal (x) components:

F_y=ma_y (2)

F_x=ma_x (3)

On y we have that the acceleration is zero because the sled is not moving upward or downward, remember that the net force on y is the weight (W) pointing downward and the normal force pointing upward:

F_y=W+n=0

Following the convention that positive is upward and negative downward, W=mg=(755)(-9.81):

F_y=(755)(-9.81)+n=0

n=7406.55 N (4)

Now on the x direction we have the sum of the forces is the pulling force (T) and friction force (f)

F_x=F+f=ma_x

Choosing the direction where the horse is pulling F=1988N and the acceleration should be positive too, then:

1988+f=m(1.36)

f=(755)(1.36)-1988=-961.2 N

The negative sign means it's in the opposite direction the horse is pulling

The frictional force is related with the coefficient of kinetic friction in the next way:

|f|=\mu_k n

with μk the coefficient of kinetic friction, and n the normal force that we already found on (4), so we simply solve the last equation for μk:

\mu_k=\frac{|f|}{n}=\frac{961.2}{7406.55}=0.13

4 0
3 years ago
Do you know any good books about physics and math?​
horrorfan [7]
What Is Mathematics? Is a book about math


A book about physics /A Brief History of Time
5 0
3 years ago
H²O ( water ) is an example of ____, as it is made up of two elements. ​
Aloiza [94]

Answer: Hydrogen atoms and oxygen atoms

Explanation:

The H stands for Hydrogen and there is two of those and the O is Oxygen and there is one of them giving you H2O

4 0
3 years ago
Read 2 more answers
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