Question

A race car travels a circular track at an average rate of 135 mi/hr. The radius of the track is 0.450 miles. What is the centripetal acceleration of the car?

Answer 1

135 * 135 / 0.450 = 40,500 mi/hr2 

Answer 2

Answer : $a_c=40500\ mi/h^2$.

Explanation :

It is given that,

Velocity of a race car, v = 135 mi/hr

Radius of the track, r = 0.45 miles

We know that the centripetal acceleration is defined as :

$a_c=\dfrac{v^2}{r}$

r is the radius of the circle.

$a_c=\dfrac{(135\ mi/hr)^2}{0.45\ mi}$

$a_c=40500\ mi/h^2$

So, the centripetal acceleration of the car is $a_c=40500\ mi/h^2$.

Hence, this is the required solution.