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Digiron [165]
3 years ago
7

A race car travels a circular track at an average rate of 135 mi/hr. The radius of the track is 0.450 miles. What is the centrip

etal acceleration of the car?
Physics
2 answers:
kenny6666 [7]3 years ago
7 0
135 * 135 / 0.450 = 40,500 mi/hr2 

PilotLPTM [1.2K]3 years ago
4 0

Answer : a_c=40500\ mi/h^2.

Explanation :

It is given that,

Velocity of a race car, v = 135 mi/hr

Radius of the track, r = 0.45 miles

We know that the centripetal acceleration is defined as :

a_c=\dfrac{v^2}{r}

r is the radius of the circle.

a_c=\dfrac{(135\ mi/hr)^2}{0.45\ mi}

a_c=40500\ mi/h^2

So, the centripetal acceleration of the car is a_c=40500\ mi/h^2.

Hence, this is the required solution.

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