Given :
A mover slides a refrigerator weighing 650 N at a constant velocity across the floor a distance of 8.1 m.
The force of friction between the refrigerator and the floor is 230 N.
To Find :
How much work has been performed by the mover on the refrigerator.
Solution :
Since, refrigerator is moving with constant velocity.
So, force applied by the mover is also 230 N ( equal to force of friction ).
Now, work done in order to move the refrigerator is :
Hence, this is the required solution.
Answer:
The maximum value of the driving force is 1044.01 N.
Explanation:
Given that,
Weight of the object, W = 50 N
Force constant of the spring, k = 210 N/m
The system is undamped and is subjected to a harmonic driving force of frequency 11.5 Hz.
Amplitude, A = 4 cm
We need to find the maximum value of the driving force. The force is given by the product of mass and maximum acceleration as :
.....(1)
A is amplitude
m is mass,
is angular frequency
Angular frequency is given by :
Equation (1) becomes :
So, the maximum value of the driving force is 1044.01 N.