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snow_tiger [21]
3 years ago
13

An object with a mass of 1.5kg changes its velocity from +15m/s to +22 during a time interval of 3.5 seconds. What Impulse was d

elivered to the object
A: 3.0 N•s
B: 11 N•s
C: 25 N•s
D: 56 N•s
Physics
1 answer:
Shalnov [3]3 years ago
7 0

B: 11 N.s is the answer

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Whats the purpose of the metal strip under a car?
mezya [45]

Answer:

It ensures the doors seal properly when closed. This seal will fend off the elements, and prevent water from leaking inside the vehicle. It is further used on windows to seal and protect the windows.

Explanation:

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3 years ago
What about electrons allow them to be some of the fastest traveling subatomic particles?
rewona [7]
They're extremely small, occupying a very small volume, to the point where something like wind resistance that we think about with accelerating large objects like planes becomes completely irrelevant. A rogue electron can fly straight through most solid objects through the "empty space" between atoms. Their mass is also extremely small, 9.1*10⁻³¹ kg, making them relatively easy to accelerate to near light speeds (in comparison to other forms of matter) as it takes very little energy to set them into motion. Particle accelerators accelerate electrons to 99% of the speed of light in the real world every day.
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4 years ago
A uniform thin spherical shell of mass M=2kg and radius R=0.23m is given an initial angular speed w=18.3rad/s when it is at the
Rashid [163]

Answer:

47.8rad/s

Explanation:

For energy to be conserved.

The potential energy sustain by the object would be equal to K.E

P.E = m× g× h = 2 × 9.81× 3.5= 68.67J

Now K.E = 1/2 × I × (w1^2 - w0^2)

I = 2/3 × M × R2

= 2/3 × 2 × (0.23)^2= 0.0705

Hence

W1 = final angular velocity

Wo = initial angular velocity

From P.E = K.E we have;

68.67J = 1/2 × 0.0705 × (w1^2 - w0^2)

(w1^2 - w0^2) = 1948.09

W1^2 = 1948.09 + (18.3^2)

W1^2=2282.98

W1 = √2282.98

=47.78rad/s

= 47.8rad/s to 1 decimal place.

7 0
3 years ago
CYCLONE SAFETY MEASURES
Slav-nsk [51]

Answer:

Below are NDMA's recommended safety measures:

Ignore rumours, Stay calm, Don't panic.

Keep your mobile phones charged for emergency communication; use SMS.

Listen to the radio, watch TV, read newspapers for weather updates.

Keep cattle/animals untied to ensure their safety.

5 0
3 years ago
Read 2 more answers
A baseball player slides into third base with an initial speed of 4.0 m/s . if the coefficient of kinetic friction between the p
satela [25.4K]
The work done by the friction force to stop the player is equal to his loss of kinetic energy:
W= \Delta K

The work done by the friction force is the magnitude of the force \mu m g times the distance covered by the player, d:
W= \mu mg d

The loss in kinetic energy is simply equal to the initial kinetic energy of the player, since the final kinetic energy is zero (the player comes to rest):
\Delta K=K_i =  \frac{1}{2}mv^2

Substituting into the first equation, we get:
\mu m g d=  \frac{1}{2}mv^2
from which we find d, the distance covered by the player:
d= \frac{v^2}{2 \mu g}= \frac{(4.0 m/s)^2}{2 \cdot 0.4 \cdot 9.81 m/s^2}=2.04 m
4 0
3 years ago
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