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stiv31 [10]
3 years ago
13

-3.8x = -7.4 Is x=2 is a solution

Mathematics
1 answer:
Lana71 [14]3 years ago
6 0
No

The anser is x= -11,2
You might be interested in
Solve.and show your work
Marysya12 [62]

Answer:

a) x > − 24 \frac{3}{4}

b) x < − 3

c) q < 56

Step-by-step explanation:

a) −2/5x−9<9/10

<=> 2/5x + 9 > − 9/10

<=> 2/5x > − 9/10 − 9

<=> 2×2/2×5x > − 9/10 − 9×10/10

<=> 4/10x > − 99/10

<=> x > − 99/4

<=> x > − 24 \frac{3}{4}

b) 4x+6<−6

<=> 4x < − 6 − 6

<=> 4x < − 12

<=> x < − 12/4

<=> x < − 3

c) q+12−2(q−22)>0

<=> q+12−2q −2×(−22)>0

<=> (q−2q) + (12+ 44) >0

<=> −q + 56 >0

<=> q < 56

8 0
3 years ago
What is 13 = t/9 - 1 I NEED HELPP!!!!!!!!!!!!!!!!!!!
Gekata [30.6K]
T = 126.

13 = t/9 - 1 multiply both sides by 9
117 = t - 9 move terms
-t = -9 - 117
-t = -126 change the signs
t = 126
3 0
3 years ago
55% decrease followed by a 25% increase
Lostsunrise [7]
Changed both of them to a fraction 
7 0
4 years ago
What is this function written in vertex form? f(x) = (x –1)2 – 7 f(x) = (x 1)2 – 7 f(x) = (x –1)2 – 5 f(x) = (x 1)2 – 5
Maslowich

The vertex form of all expressions is given below.

We have given that the expressions

We have to write the function in vertex form.

<h3>What is the vertex form of the equation?</h3>

The vertex form of a quadratic function is given by f (x) = a(x - h)^2 + k, where (h, k) is the vertex of the parabola.

Therefore the first equation

f(x)=(x-1)^2-7

it can be written as

f(x)=1(x-1)^2+(-7)

The second equation can be written as

f(x) = (x+1)^2 -7

vertex for is,

f(x)=1(x-(-1))^2+(-7)

The third equation is,

f(x) = (x -1)^2 - 5

Vertex form is,

f(x)=1(x-1)^2+(-5)

Forth equation is,

f(x) = (x +1)^2 +(- 5)

Vertex form is,

f(x) =1 (x -(-1))^2 +(- 5)

To learn more about the vertex form visit:

brainly.com/question/17987697

#SPJ1

3 0
2 years ago
For f(x)=2/(x+1) and g(x)=2x+3, find the following:
pshichka [43]
Im unsure about g(f(4)) though.

7 0
3 years ago
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