Determine which value is equivalent to | f ( i ) | if the function is: f ( x ) = 1 - x. We know that for the complex number: z = a + b i , the absolute value is: | z | = sqrt( a^2 + b^2 ). In this case: | f ( i )| = | 1 - i |. So: a = 1, b = - 1. | f ( i ) | = sqrt ( 1^2 + ( - 1 )^2) = sqrt ( 1 + 1 ) = sqrt ( 2 ). ANSWER IS C. sqrt( 2 )
<h2>
The required positive number is 7.</h2>
Step-by-step explanation:
Let the number = x
To find, the positive number = ?
According to question,
⇒ 
- 3x - 28 = 0
By Factorisation method,
⇒ - 7x + 4x - 28 = 0
⇒ x(x - 7) + 4(x - 7) = 0
⇒ (x - 7)(x + 4) = 0
⇒ x - 7 = 0 or, x + 4 = 0
⇒ x = 7 or, x = - 4 [ - 4 is a negative number)
⇒ x = 7
Thus, the required positive number is 7.
This only happens when the ordinary ratio is greater than one, the terms of the sequence will get bigger and bigger, and if you add larger numbers you won't get a definitive answer.
Answer:
x = -14
Step-by-step explanation:
Step 1: Write equation
4(x + 2) = 3(x - 2)
Step 2: Solve for <em>x</em>
- Distribute: 4x + 8 = 3x - 6
- Subtract 3x on both sides: x + 8 = -6
- Subtract 8 on both sides: x = -14
Step 3: Check
<em>Plug in x to verify it's a solution.</em>
4(-14 + 2) = 3(-14 - 2)
4(-12) = 3(-16)
-48 = -48
<span>Finding the square root.</span>
