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Harrizon [31]
3 years ago
8

Help Hurry

Mathematics
1 answer:
Lesechka [4]3 years ago
6 0

Answer:

1 cubed 1

2 cubed 8

3 cubed 27

4 cubed 64

5 cubed 125

6 cubed 216

10 cubed 1,000

Cube Root of 1 is 1

Cube Root of 8 is 2

Cube Root of 27 is 3

Cube Root of 64 is 4

Cube Root of 125 is 5

Cube Root of 216 is 6

Cube Root of 1,000 is 10

Step-by-step explanation:

To find the cube of a number multiply that number by itself three times and to find the cube root of a number find one perfect cube less than the original number and then find one greater than the original number and then round if you need to.

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Using the line of the best fit how many gallons of water with 13 runners be expected to drink
xz_007 [3.2K]

128oz

i kinda had to guess but i got 128oz because

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its also known that most runners drink less then 16oz per hour when racing also (480ml) j lettin ya know hope it helped

8 0
3 years ago
If Anthony has twice as nickels as one and one has 15 more nickels than Maria what is the value in dollars of Anthony's Nickels
worty [1.4K]

Answer:

Anthony has $2.10

Step-by-step explanation:

If Maria has 6 nickels and one has 15 more nickels than Maria, one has a total of 21 nickels. Since Anthony has twice the amount of nickels as One, you would multiply 21 by 2 to get a total of 42. It takes 20 nickels to make a dollar. If you divide 42 by 20 you get 2.1, which is equivaldnt to $2.10

4 0
3 years ago
HELP! I NEED THIS ANSWER, WILL GIVE BRAINLIEST
velikii [3]

Answer:

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5 0
4 years ago
Find the taylor series for f(x) centered at the given value of a. [assume that f has a power series expansion. do not show that
RUDIKE [14]

The taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16 (x+4)^{2}/2!+...........

Given a function f(x)=9/x,a=-4.

We are required to find the taylor series for the function f(x)=8/x centered at the given value of a and a=-4.

The taylor series of a function f(x)=f(a)+f^{1}(a)(x-a)/1!+ f^{11}(a)(x-a)^{2} /2! +f^{111}(a)(x-a)a^{3}/3!+..........

Where the terms in f prime f^{1}(a) represent the derivatives of x valued at a.

For the given function.f(x)=8/x and a=-4.

So,f(a)=f(-4)=8/(-4)=-2.

f^{1}(a)=f^{1}(-4)=-8/(-4)^{2}

=-8/16

=-1/2

The series of f(x) is as under:

f(x)=f(-4)+f^{1}(-4)(x+4)/1!+  f^{11}(-4)(x+4)^{2}/2!.............

=8/(-4)-8/(-4)^{2} (-4)(x+4)/1!+  24/(-4)^{3} (-4)(x+4)^{2}/2!.............

=-2+2(x+4)/1!-24/16 (x+4)^{2}/2!+...........

Hence the taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16 (x+4)^{2}/2!+...........

Learn more about taylor series at brainly.com/question/23334489

#SPJ4

3 0
1 year ago
Please help me babes!!
abruzzese [7]
The correct answer would be C) CBA-EFD 
6 0
3 years ago
Read 2 more answers
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