Answer:
a)
b) a= 1.79 m/s²
θ = 41.98⁰
Explanation:
arc radius = 12 m
constant speed = 4.00 m/s
(a) centripetal acceleration
= 1.33 m/s²
(b) now we have given
now,
a= 1.79 m/s²
direction
θ = 41.98⁰
Answer:
Low satellite has high orbital velocity
Explanation:
let v be the orbital speed of the satellite orbiting at a height h is given by
where, M be the mass of planet, r be the radius of planet and h be the height of planet from the surface of planet.
here we observe that more be the height lesser be the orbital velocity.
So, a satellite which is at low height has high orbital velocity.
Assuming this is a neutral atom, protons = electrons = atomic number
Since there are 8 positively charged particles or protons, there are also 8 electrons and that element's atomic number is 8. Neutrons is atomic mass minus atomic number which is 7 neutrons in this case.This element is therefore oxygen.