If you are given three different capacitors, how many different combinations of capacitance can you produce, using all capacitor
s in your circuits? Draw those circuits
1 answer:
Answer:
5
Explanation:
Let there are three capacitances, C1, C2, and C3.
Combination I:
All the three are connected in series combination.
Combination II:
All the three are connected in parallel combination.
Combination III:
C1, C2 are in parallel and then C3 in series.
Combination IV:
C1, C3 are in parallel and then C2 in series.
Combination V:
C3, C2 are in parallel and then C1 in series.
You might be interested in
Answer:
AB = 29
Explanation:
For a better understanding, we must work this problem in a graphic way. In the attached image we can see the solution.
First, we draw a vertical dotted lines from the point J & K to the line ML, then we can see two new portions with the same length. Then with this simple analysis:
2x = 39 - 19
x = 10
Then we know that x = 10, another important data to find the answer is that the AB line is located in the midpoints of the legs. We also can see the right triangle MJ and the dotted line.
Now for every single right triangle, no matter its size and relationship between the vertical and the horizontal lengths, if some point is located in the hypotenuse (leg) at the middle of its length. This will be proportional to the vertical and the horizontal cathetus, therefore we will have the middle point on those two lines.
So, the AB line will be the sum of JK plus two times 5
AB = 19 + 5 + 5 = 29
