Answer:
D
Explanation:
This is a beta decay so the atomic number goes up by one thus becoming an argon isotope in the process.
Answer:
Heat energy required = 252000J or 252KJ.
Explanation:
<u>Given the following data;</u>
Mass = 3kg
Temperature = 20ºC
Specific heat capacity of water = 4200 J/kg°C
To find the heat energy required;
Heat capacity is given by the formula;
Where;
- Q represents the heat capacity or quantity of heat.
- m represents the mass of an object.
- c represents the specific heat capacity of water.
- t represents the temperature.
Substituting into the equation, we have;
Q = 252000 Joules or 252 Kilojoules.
It seems like the question is asking for the frequency.
Given:
Time period (T) = 2.4 sec
Frequency (f) =?
We know that the formula for frequency is:
Frequency (f) = 1/time period (T)
= 1 / 2.4 s
= 0.42 Hz. is the frequency for this problem.
Answer:
Required rate of return = 18.5 %
Explanation:
given,
rate of inflection = 4 %
risk free rate = 3 %
market risk premium = 5 %
firm has a beta = 2.30
rate of return has averaged 15.0% over the last 5 years
now,
Nominal risk free rate = risk free rate + inflation
= 3% + 4%
= 7%
Required rate of return = Nominal risk free rate + β (RPM)
= 7% + 2.3 x 5.0%
Required rate of return = 18.5 %
Answer:
(a) 0.177 m
(b) 16.491 s
(c) 25 cycles
Explanation:
(a)
Distance between the maximum and the minimum of the wave = 2A ............ Equation 1
Where A = amplitude of the wave.
Given: A = 0.0885 m,
Distance between the maximum and the minimum of the wave = (2×0.0885) m
Distance between the maximum and the minimum of the wave = 0.177 m.
(b)
T = 1/f ...................... Equation 2.
Where T = period, f = frequency.
Given: f = 4.31 Hz
T = 1/4.31
T = 0.23 s.
If 1 cycle pass through the stationary observer for 0.23 s.
Then, 71.7 cycles will pass through the stationary observer for (0.23×71.7) s.
= 16.491 s.
(c)
If 1.21 m contains 1 cycle,
Then, 30.7 m will contain (30.7×1)/1.21
= 25.37 cycles
Approximately 25 cycles.