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2 years ago

9 members of a club. Need 3 officers. How many combinations are possible.

Mathematics

1 answer:

irina [24]2 years ago

3 0

Answer:

I think its 3 combos

Step-by-step explanation:

9÷3=3 combos?

Hope this helps :D

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What is the distance between the points 4,10 and -3,-14 on the coordinate plane

Kryger [21]

Answer:

Step-by-step explanation:

Here we are supposed to find the distance between two coordinates ( 4,10) and (-3,-14).

Let us do this step by step with detailed explanation.

We will use distance formula in order to find the distance between them. The distance formula is given as

$D=\sqrt{(x_{2}-x_{1})^{2} +(y_{2}-y_{1})^{2} }$

Here we have

$x_{2}=-3\\x_{1}=4\\y_{2}=-14\\y_{1}=10\\$

Replacing them in the formula we get

$D=\sqrt{(-3-4)^{2} +(-14-10)^{2} }\\D=\sqrt{(-7)^{2} +(-24)^{2} }\\D=\sqrt{49+ 576 }\\D=\sqrt{625 }\\D=25\\$

Hence our distance is 25 units

8 0

3 years ago

HELP PLEASE, I don’t understand:(!

blondinia [14]

Does that say find M/_T. ( /_ is my way of making the angle symbol

4 0

3 years ago

The expression 14s(s - 1) can be used to find

Fantom [35]

Answer:

B. The variable s represents the number of students in each class.

C. The coefficient 14 represents the number of classes in the 9th grade.

Step-by-step explanation:

The total number can be found by multiplying the number of the things with the number of people producing it. For example if 5 boys make 5 colored ropes the total number of ropes will be 5*5= 25.

In this question the combinations rule is used for variuos number of classes which are 14. Now we have to find the number of students which are s (s-1). Suppose s= 6 so the number of students would be 6(6-1) = 6(5) = 30

We will multiply the number of classes 14 with the number of students s(s-1) to get the total number of cards produced.

6 0

2 years ago

Find two consecutive even integers whose sum is 30

Yuliya22 [10]

Answer:

14 & 16

Step-by-step explanation:

30÷2=15

15+15=30, so we can make the conclusion...

14+16=30

3 0

2 years ago

Solve the system of equations using matrices. Use the Gauss- Jordan elimination method And find a solution set

KATRIN_1 [288]

$\begin{gathered} x+y+z=4 \\ x-y-z=0 \\ x-y+z=8 \\ \text{The system using matrix is} \\ \begin{bmatrix}{1} & {1} & {1}, & {4} \\ {1} & {-1} & {-1,} & {0} \\ {1} & {-1} & {1,} & {8}{}{}\end{bmatrix}\rightarrow F2=F2-F1=\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {-2} & {-2,} & {-4} \\ {1} & {-1} & {1,} & {8}{}{}\end{bmatrix} \\ \rightarrow F3=F3-F1=\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {-2} & {-2,} & {-4} \\ {0} & {-2} & {0,} & {4}{}{}\end{bmatrix}\rightarrow F2=-\frac{1}{2}F2 \\ =\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {1} & {1,} & {2} \\ {0} & {-2} & {0,} & {4}{}{}\end{bmatrix}\rightarrow F3=F3+2F2=\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {1} & {1,} & {2} \\ {0} & {0} & {2,} & {8}{}{}\end{bmatrix}\rightarrow F3=\frac{1}{2}F3 \\ =\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {1} & {1,} & {2} \\ {0} & {0} & {1,} & {4}{}{}\end{bmatrix}\rightarrow F2=F2-F3=\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {1} & {0,} & {-2} \\ {0} & {0} & {1,} & {4}{}{}\end{bmatrix} \\ \rightarrow F1=F1-F3=\begin{bmatrix}{1} & {1} & {0}, & {0} \\ {0} & {1} & {0,} & {-2} \\ {0} & {0} & {1,} & {4}{}{}\end{bmatrix}\rightarrow F1=F1-F2 \\ =\begin{bmatrix}{1} & {0} & {0}, & {2} \\ {0} & {1} & {0,} & {-2} \\ {0} & {0} & {1,} & {4}{}{}\end{bmatrix} \\ \text{Therefore, the solution is }x=2,\text{ y=-2 and z=4} \end{gathered}$

6 0

1 year ago