A local hamburger shop sold a total of 712 burgers on Tuesday
There are 62 more cheeseburgers than hamburgers
let cheeseburers = c
let hamburgers = h
h + 62 = c
c + h = 712
Plug in h + 62 for c
(h + 62) + h = 712
2h + 62 = 712
2h + 62 (-62) = 712 (-62)
2h = 650
2h/2 = 650/2
h = 325
There are 325 hamburgers sold on Tuesday
c = 325 + 62
c = 387
<em>There are 387 chesseburgers sold on tuesday </em>(in case you were wondering)
hope this helps
Answer:
y = x² − 6x − 27
Step-by-step explanation:
To distribute, you can use something called FOIL. It stands for First, Outer, Inner, Last.
First, multiply the First term in each factor.
x · x = x²
Now multiply the Outer terms in each factor.
x · 3 = 3x
Next multiply the Inner terms in each factor.
-9 · x = -9x
Finally, multiply the Last terms in each factor.
-9 · 3 = -27
Add them all up:
x² + 3x − 9x − 27
x² − 6x − 27
Answer:
IM SUCH AN INFLUENCER :D
Step-by-step explanation:
B. both r correct
when it’s 2x it goes up two over one. rise/run, 2/1
for the table if you look at the graph when x=1 then y=2 and if x=2 then y=4