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uranmaximum [27]
3 years ago
8

As a result of air at the top of a barometer the height of the mercury column is 73.5cm when it should be 75.0 cm the volume of

the space above the mercury is 8.0cmcube. Calculate the correct barometric height when the barometer reads 74.0cm and the volume of the space above the mercury is 6.0cmcube.
Physics
1 answer:
MakcuM [25]3 years ago
5 0

Explanation:

Using p1p1=p2p2

(75-73.5)x8=(X - 74)X 6

1.5 X 8= 6x-444

12=6x-444 (add 12)

6x=456 (divide by 6)

X= 76cm

Therefore the answer for the barometric height is 76cm

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What is the reflectivity of a glass surface (n =1.5) in air (n = 1) at an 45° for (a) S-polarized light and (b) P-polarized ligh
Goshia [24]

Answer:

a) R_s = 0.092

b) R_p = 0.085

Explanation:

given,

n =1.5 for glass surface

n = 1 for air

incidence angle = 45°

using Fresnel equation of reflectivity of S and P polarized light

R_s=\left | \dfrac{n_1cos\theta_i-n_2cos\theta_t}{n_1cos\theta_i+n_2cos\theta_t} \right |^2\\R_p=\left | \dfrac{n_1cos\theta_t-n_2cos\theta_i}{n_1cos\theta_t+n_2cos\theta_i} \right |^2

using snell's law to calculate θ t

sin \theta_t = \dfrac{n_1sin\theta_i}{n_2}=\dfrac{sin45^0}{1.5}=\dfrac{\sqrt{2}}{3}

cos \theta_t =\sqrt{1-sin^2\theta_t} = \dfrac{sqrt{7}}{3}

a) R_s=\left | \dfrac{\dfrac{1}{\sqrt{2}}-\dfrac{1.5\sqrt{7}}{3}}{\dfrac{1}{\sqrt{2}}+\dfrac{1.5\sqrt{7}}{3}} \right |^2

R_s = 0.092

b) R_p=\left | \dfrac{\dfrac{\sqrt{7}}{3}-\dfrac{1.5}{\sqrt{2}}}{\dfrac{\sqrt{7}}{3}+\dfrac{1.5}{\sqrt{2}}} \right |^2

R_p = 0.085

3 0
3 years ago
What are the 3 Laws of Newtonian Mechanics
Katyanochek1 [597]

In the first law, an object will not change its motion unless a force acts on it. In the second law, the force on an object is equal to its mass times its acceleration. In the third law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction

7 0
3 years ago
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A bird has a kinetic energy of 3 J and a potential energy of 25 J. What is the mechanical energy of the bird?
Ahat [919]

Answer:

28 J

Explanation:

Mechanical energy is the sum of kinetic and potential energy in an object that is used to do work. In other words, it is energy in an object due to its motion or position, or both.

In physics, mechanical energy (Emech) is the energy associated with the motion and position of an object usually in some force field.

Therefore:

ME = KE + PE = 25 + 3 = 28 J

8 0
3 years ago
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A jet plane traveling 1890 km/h (525 m/s) pulls out of a dive by moving in an arc of radius 5.20 km. What is the plane's acceler
Tema [17]

Answer:

Acceleration of the plane, a = 5.4 g

Explanation:

It is given that,

Speed of the jet plane, v = 1890 km/h = 525 m/s

Radius of the arc, r = 5.20 km = 5200 m

The plane is moving in the circular path, the centripetal acceleration will act on it. It is given by :

a=\dfrac{v^2}{r}

a=\dfrac{(525\ m/s)^2}{5200\ m}

a=53.004\ m/s^2

We know that, the value of g is, g=9.8\ m/s^2

\dfrac{a}{g}=\dfrac{53.004\ m/s^2}{9.8\ m/s^2}=5.4

a=5.4\times g

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3 years ago
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SVEN [57.7K]

Answer:

  • <u>Option:(D)-</u>

<em>"Io orbits Jupiter on an elliptical orbit, due to orbital resonances with other satellites."</em>

Explanation:

  • <u>"Io" moon of Jupiter:</u>

The Io is one of the four moons of Jupiter, as it rotates around the planet in an elliptical orbit, due to orbital resonance with other satellites. As due to the rotational motion of the moon, while orbiting the planet and having a large amount of gravitational pull on them there is a net amount of heat between the two heavenly bodies in the solar system. As the moon is very small in size as compared to giant celestial body, the crust of the moon is distorted by the unequal force of the gravity on each of its side by the planet causing a distortion of the moon's over all shape.

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