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NARA [144]
3 years ago
14

Why would you wanna know a cure for all sickness.?

Physics
1 answer:
Alchen [17]3 years ago
4 0

Answer:

because if someone close to u gets sick you would know how to cure it

You might be interested in
If a 400 watt motor is left on for 10 minutes, assuming no energy is lost to friction, how fast could a 100 kg cart be moving?
Verdich [7]

Answer:

69.28 m/s

Explanation:

From the question given above, the following data were obtained:

Power = 400 Watt

Time (t) = 10 minutes

Mass (m) = 100 Kg

Velocity (v) =?

Next, we shall convert 10 mins to seconds (s). This can be obtained as follow:

1 min = 60 s

Therefore,

10 mins = 10 × 60

10 mins = 600 s

Next, we shall determine the energy. This can be obtained as follow:

Power = 400 Watt

Time (t) = 600 s

Energy (E) =?

E = Pt

E = 400 × 600

E = 240000 J

Finally, we shall determine how fast the cart is moving. This can be obtained as illustrated below:

Mass (m) = 100 Kg

Energy (E) = Kinetic energy (KE) = 240000 J

Velocity (v) =?

KE = ½mv²

240000 = ½ × 100 × v²

240000 = 50 × v²

Divide both side by 50

v² = 240000 / 50

v² = 4800

Take the square root of both side

v = √4800

v = 69.28 m/s

Thus, the cart is moving with a speed of 69.28 m/s

5 0
3 years ago
Used to measure mass
Lemur [1.5K]
Measuring mass with a balance
5 0
3 years ago
Read 2 more answers
As a train accelerates away from a station, it reaches a speed of 4.9 m/s in 5.1 s. If the train's acceleration remains constant
vodomira [7]
Acceleration is the rate of change of the velocity of a moving object. To determine the speed the object has at a certain time, we need to determine the acceleration first by dividing the speed with the time given. We do as follows:

acceleration = 4.9 m/s / 5.1 s = 0.96 m/s^2

To determine the velocity after 7.1 s, we multiply 7.1 s to the acceleration. 

speed or velocity = 0.96 x 7.1 = 6.52 m/s
3 0
3 years ago
Read 2 more answers
Electrons (mass m, charge –e) are accelerated from rest through a potential difference V and are then deflected by a magnetic fi
adell [148]

Answer:

r=\dfrac{1}{B}\sqrt{\dfrac{2Vm}{e}}

Explanation:

Let m and e are the mass and charge of an electron. It is accelerated from rest through a potential difference V and are then deflected by a magnetic field that is perpendicular to their velocity. Let v is the velocity of the electron. It can be calculated as :

\dfrac{1}{2}mv^2=eV

v=\sqrt{\dfrac{2eV}{m}}

When the electron enters the magnetic field, the centripetal force is balanced by the magnetic force as :

\dfrac{mv^2}{r}=evB

r=\dfrac{mv}{eB}

or

r=\dfrac{1}{B}\sqrt{\dfrac{2Vm}{e}}

So, the radius of the resulting electron trajectory is \dfrac{1}{B}\sqrt{\dfrac{2Vm}{e}}. Hence, this is the required solution.

8 0
3 years ago
Calculate the percentage increase in length of a wire of diameter 2.2 mm stretched by a load of
vesna_86 [32]

Answer:

0.21%

Explanation:

We are given;

Mass; m = 100 kg

Diameter; d = 2.2 mm = 2.2 × 10^(-3) m

Young's modulus; E = 12.5 x 10^(10) N/m².

Formula for area is;

A = πd²/4

A = (π/4) x (2.2 x 10^(-3))²

A = 3.8 x 10^(-6) m²

Force; F = mg

g is acceleration due to gravity and has a constant value of 9.8 m/s²

F = 100 × 9.8

F = 980 N

Formula for young's modulus is;

E = Stress/strain

Formula for stress = F/A

Formula for strain = ΔL/L

Thus;

E = (F/A)/(ΔL/L)

Making ΔL/L the subject, we have;

ΔL/L = (F/A)/E

Plugging in the relevant values;

ΔL/L = 980/(3.8 x 10^(-6) × 12.5 × 10^(10))

ΔL/L = 0.0021

Then percentage increase in length of a wire = 0.0021 × 100% = 0.21%

8 0
3 years ago
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