Answer:
Your missing a number and your answer is 12
Step-by-step explanation:
Answer: 24-(8/2)+6=26
3+6X2/3=7
4X4+3=19
Step-by-step explanation:
So it is asking you to group like term so
x terms can be grouped/added/subtracted to other x terms, but not to x^2 or x^3 terms
x^2 terms to x^2 and so on so
1. 9-3k+5k=
9+(5k-3k)=
9+2k
2. k^2+2k+4k=
k^2+(2k+4k)=
k^2+6k=
I: y<2*x
II: y<8
III: x>2
a: (5,3):
I: 3<2*5
3<10 ?yes
II: 3<8 ?yes
III: 5>2 ?yes
This is a solution
b: (6,0):
I: 0<2*6
0<12 ?yes
II: 0<8 ?yes
III: 6>2 ?yes
This is a solution
c: (3,3):
I: 3<2*3
3<6 ?yes
II: 3<8 ?yes
III: 3>2 ?yes
This is a solution
d: (1,-4):
I: -4<2*1
-4<2 ?yes
II: -4<8 ?yes
III: 1>2 ?no
This is not a solution
e: (4,-2):
I: -2<2*4
-2<8 ?yes
II: -2<8 ?yes
III: 4>2 ?yes
This is a solution
f: (5,9):
I: 9<2*5
9<10 ?yes
II: 9<8 ?no
This is not a solution
so a,b,c,e are solutions and d,f not
1) -10x+y=4
Now, you should substitute x in every situation.
* x=-2 <em>=> -10*(-2)+y=4... 20+y=4... <u>y=-16</u></em>
<em />* x=-1 =>-10*(-1)+y=4... 10+y=4... <u>y=-6</u>
<u />*x=0 => -10*0+y=4... <u>y=4</u>
<u />* x=1 => -10*1+y=4... -10+y=4... <u>y=14</u>
<u />* x=2 => -10*2+y=4... -20+y=4... <u>y=24</u>
<u>2)</u> -5x-1=y
For example: x=0
-5*0-1=-1
<u>
</u>
