Question

It takes a soccer player 3 seconds so reduce his speed to 3.1 m/s. What is the magnitude of his acceleration?

Answer 1

Acceleration =change in velocity/change in time.
So final speed minus initial velocity/time
3.1-v/2=a

Answer 2

Answer: The magnitude of his acceleration is $1.033 m/s^2$.

Explanation:

Final velocity of the player= v = 3.1 m/s

Initial velocity of the player = u = 0 m/s

Time taken  by the player = 3 s

Acceleration of the soccer player = a

Using first equation of the motion:

$v=u+at$

$a=\frac{v-u}{t}=\frac{3.1- m/s-0 m/s}{3 s}=1.033 m/s^2$

The magnitude of his acceleration is $1.033 m/s^2$.