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Elis [28]
3 years ago
6

A commuter backs her car out of her garage with an acceleration of . (a) How long does it take her to reach a speed of 2.00 m/s

Physics
1 answer:
aliya0001 [1]3 years ago
3 0

Question: A commuter backs her car out of her garage with an acceleration of 1.4 m/s² (a) How long does it take her to reach a speed of 2.00 m/s

Answer:

1.43 s

Explanation:

Applying,

a = (v-u)/t........... Equation 1

Where a = acceleration, v = final velocity, u = initial velocity, t = time

make t the subject of the equation

t = (v-u)/a........... Equation 2

From the question,

Given: v = 2 m/s, u = 0m/s (from rest), a = 1.4 m/s²

Substitute into equation 2

t = (2-0)/1.4

t = 1.43 s

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The Yerkes Primate Center has existed (or has been in existence) since the 1960s and has a focus in two major areas: Immunology
dybincka [34]

Answer:

Research towards increasing the understanding of progressive illnesses, such as Parkinson’s and Alzheimer’s diseases.

Explanation:

The Yerkes Primate center was established in 1930 by Robert Yerkes, in Orange Park, Florida. But was moved to its present location in Emory University.

The center has its focus on two major area of research, which are  Immunology and Vaccine, and research towards  increasing the understanding of progressive illnesses, such as Parkinson’s and Alzheimer’s diseases.

6 0
3 years ago
Bella makes the 2.5m distance to her food bowl in 9.1 seconds. What is her average velocity?
e-lub [12.9K]
  • Distance=2.5m
  • Time=9.1s

Average Velocity=Total Distance/Total Time

\\ \sf\longmapsto \dfrac{2.5}{9.1}

\\ \sf\longmapsto 0.3m/s

7 0
3 years ago
When the mirror is rotated, the normal will turn as well, but will the incident Ray and reflected ray turn?
Inessa [10]

When a mirror is rotated . . .

-- The incident ray doesn't turn.  It's just the line from the source to the mirror. 
It would be there, in the same place, even if there was no mirror.

-- The normal turns.  It's the line perpendicular to the mirror, so it must turn
with the mirror.

-- Since the normal tuns and the incident ray doesn't, the angle between them
must change.  And since the angle of the reflected ray is equal to the angle of
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6 0
3 years ago
A pendulum is raised to a height of 0.3m above its lowest point and released. What is the velocity of the pendulum at its lowest
enyata [817]

Answer:

v = 2,425 m / s

Explanation:

A simple pendulum has anergy stored at the highest point of the path and this energy is conserved throughout the movement.

highest point

           Em₀ = U = m g y

lowest point

          Em_{f} = K = ½ m v²

         Em₀ = Em_{f}

        mg y = ½ m v²

        v = √ 2gy

let's calculate

        v = √ (2 9.8 0.3)

        v = 2,425 m / s

3 0
3 years ago
PLEASE HELP ONLY 5 QUESTIONS
Phantasy [73]
1. b or c
2. c
3. a? or d
4.
5. a
8 0
3 years ago
Read 2 more answers
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