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4 years ago

Help please!!! Ty to anyone who answeres

Mathematics

1 answer:

Alja [10]4 years ago

6 0

Answer:

Scale factor=2

The perimeter of the enlarged figure is 19

The area of the enlarged figure is 4 times the area of the original figure

Step-by-step explanation:

Scaling

There are two figures, the red rectangle (original) and the blue rectangle (enlarged).

To find the scale factor we directly compare the height of both rectangles and note:

height of original rectangle=1.5

height of enlarged rectangle=3

Thus, the scale factor is 3/1.5 = 2

Scale factor=2

The original perimeter is calculated as:

P1=2*1.5+2*3.25=3+6.5=9.5

The perimeter of the enlarged figure is 2 times the original perimeter

P2=2*9.5=19

The perimeter of the enlarged figure is 19

To calculate the area of the enlarged figure, we use

A2=H2*W2

Where H2 and W2 are the height and width of the enlarged figure.

Since

H2=2*H1

W2=2*W1

A2=4*A1

The area of the enlarged figure is 4 times the area of the original figure

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Ramla bought a sheet of 100 stamps from the post office for $39. what was the price of each stamp?

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3 years ago

VashaNatasha [74]

Answer:

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = - 2 and c = - 2 , then

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To find the x- intercept let y = 0 in the equation and solve for x , that is

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3 years ago

Find the minimum y-value on the graph of y=f(x) F(x) = 7x^2 + 7 - 6

Kisachek [45]

Answer:

The minimum y-value is

$y=-\frac{31}{4}$ or $y=-7.75$

Step-by-step explanation:

we have

$f(x)=7x^{2}+7x-6$

This is the equation of a vertical parabola open up

The vertex is the minimum y-value on the graph

Convert the equation into vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$f(x)+6=7x^{2}+7x$

Factor the leading coefficient

$f(x)+6=7(x^{2}+x)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$f(x)+6+1.75=7(x^{2}+x+0.25)$

$f(x)+7.75=7(x^{2}+x+0.25)$

Rewrite as perfect squares

$f(x)+7.75=7(x+0.5)^{2}$

$f(x)=7(x+0.5)^{2}-7.75$ ------> equation in vertex form

The vertex is the point (-0.5,-7.75)

therefore

The minimum is the point (-0.5,-7.75)

The minimum y-value is $y=-7.75=-7\frac{3}{4}=-\frac{31}{4}$

see the attached figure to better understand the problem

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3 years ago

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zepelin [54]

Answer:

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Step-by-step explanation:

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weqwewe [10]

Answer:

Step-by-step explanation:

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3 years ago

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