Answer:
it can overheat trying to process and from there multiple things may happen
1. the computer will recognise its overheating and automatically shutdown
2. the computer with catch on fire
3. the computer with crash the program and go back to the home screen
Explanation:
Answer:
See Explaination
Explanation:
public class testscope
{
//start of main function
public static void main(String[] args)
{
//varible declration
int i;
int x;
//loop for 10 times
for(i=0; i<10; i++)
{
//initialize value of x to 10
x = 10;
}
//the scope of variable x is visible outside of for loop
System.out.println("The value of x is: "+x);
}
}
See attachment for sample output
nb:
You can clearly see in the output of Java program the value of x is not printed and program return errors. It means the variable x declared inside for loop does not has scope outside the for loop.
THAT IS THE ANSWER 1)requires the new programmers to insert comments o their own
Answer:
If you are trying to put the events in order and they are out of order you will probaly get the question wrong so make sure the events are in order.
Explanation: