Answer:
(b) (int)(Math.random() * 101)
Explanation:
Given
--- minimum
--- maximum
Required
Java expression to generate random integer between the above interval
The syntax to do this is:
(int)(Math.random((max - min) + 1) + min)
Substitute the values of max and min
(int)(Math.random((100 - 0) + 1) + 0)
Simplify the expression
(int)(Math.random(100 + 1) + 0)
(int)(Math.random(101) + 0)
(int)(Math.random(101))
Hence, the right option is:
(b) (int)(Math.random() * 101)
Answer:
Explanation:
The following is written in Python. It takes in a file, it then reads all of the elements in the file and adds them to a list called myList. Then it sorts the list and uses the elements in that list to calculate the median. Once the median is calculated it returns it to the user. The code has been tested and the output can be seen in the image below.
def find_median(file):
file = open(file, 'r')
mylist = []
for number in file:
mylist.append(int(number))
numOfElements = len(mylist)
mylist.sort()
print(mylist)
if numOfElements % 2 == 0:
m1 = numOfElements / 2
m2 = (numOfElements / 2) + 1
m1 = int(m1) - 1
m2 = int(m2) - 1
median = (mylist[m1] + mylist[m2]) / 2
else:
m = (numOfElements + 1) / 2
m = int(m) - 1
median = mylist[m]
return median
print("Median: " + str(find_median('file1.txt')))
