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klio [65]
3 years ago
15

Synthesis route from ethane to ethanoic acid

Chemistry
1 answer:
kondor19780726 [428]3 years ago
7 0
CH₃-CH₃ + Cl₂ -----[hV]----> CH₃-CH₂Cl + HCl
CH₃-CH₂Cl + NaOH -----[H₂O]----> CH₃-CH₂-OH + NaCl
CH₃-CH₂-OH + CuO -----> CH₃-CHO + Cu + H₂O
CH₃CHO + 2Cu(OH)₂ ---[T]----> CH₃COOH + Cu₂O + 2H₂O
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Calculate the number of moles in a 14.5 gram sample of C4H10.
cricket20 [7]
Moles= mass divided by molar mass
Molar mass= 12.01(4) + 1.01(10)
                 = 58.14g/mol

Moles=14.5g / 58.14g/mol
         =0.249

Therefore there are approx 0.249 moles in a 14.5g sample of C4H10
6 0
3 years ago
Which apparatus is used in measuring a base in laboratory? Show Options a.  pipette b. measuring cylinder c. burette d. conical
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Answer:

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3 years ago
How many milliliters of water are needed to prepare a 3.5M solution of NaOH if you have .5mol of the solute
Mamont248 [21]

Answer:

1335.12 mL of H2O

Explanation:

To calculate the mililiters of water that the solution needs, it is necessary to know that the volume of the solution is equal to the volume of the solute (NaOH) plus the volume of the solvent (H2O).

From the molarity formula we can first calculate the volume of the solution:

M=\frac{solute moles}{solution volume}

Solutionvolume=\frac{solute moles}{M} =\frac{5mol}{3.5\frac{mol}{L} } =1.429L

The volume of the solution as we said previously is:

Solution volume = solute volume + solvent volume

To determine the volume of the solute we first obtain the grams of NaOH through the molecular weight formula:

MW=\frac{mass}{mol}

Mass=MW*mol=39.997\frac{g}{mol} *5mol=199.985g

Now with the density of NaOH the milliliters of solute can be determined:

d=\frac{mass}{volume}

Volume=\frac{mass}{d} =\frac{199.985g}{2.13\frac{g}{mL} } =93.88mL of NaOH

Having the volume of the solution and the volume of the solute, the volume of the solvent H2O can be calculated:

Solvent volume = solution volume - solute volume

Solvent volume = 1429 mL -  93.88 mL = 1335.12 mL of H2O

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SOVA2 [1]

Answer:

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Explanation:

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