Answer:
Acceptable Lewis structure of Diatomic Nitrogen Molecule is as follow,
:N≡N:
Explanation:
The given lewis structure is acceptable because each nitrogen atom has a complete octet and and the formal charge of each nitrogen atom is zero. So those lewis structures which has zero or least formal charges are said to be more stable and acceptable. The formal charge is calculated is,
Formal Charge = # of Valence e⁻s - [# of non-bonded e⁻ + 1/2 # of bonded e⁻]
For N,
Formal Charge = 5 - [ 2 + 6/2]
Formal Charge = 5 - [ 2 + 3 ]
Formal Charge = 5 - 5
Formal Charge = 0
Same result will come for the second N atom.
In an equation, 40kJ + 2SO₃ (g) -->2SO₂(g) + O₂(g), if pressure added, the equilibrium shifts to the left side of the reaction because it has fewer moles of gas.
<h3>What is Le Ch atelier's principle?</h3>
Le Ch atelier's principle states that if the pressure is added in a nay reaction, then the equilibrium will be shifted toward the side where there are fewer atoms.
In this case, there are fewer moles on the left side.
Thus, when pressure is added, the equilibrium shift to the left side due to Le Ch atelier's principle.
Learn more about Le Ch atelier's principle
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Answer:
1.7 Osm/L
Explanation:
Osmotic concentration is the number of osmoles (Osm) of solute per litre of solution .

An osmole is the number of moles of solute that contribute to the osmotic pressure of a solution.
1 Osm = i × n, where
i = the van't Hoff i factor and
n = the number of moles
The van't Hoff i factor is the number of solute particles obtained from 1 mol of solute.
For example,
MgSO₄(aq) ⟶ Mg²⁺(aq) + SO₄²⁻(aq)
1 mol of MgSO₄ produces 2 mol of ions in solution, so i = 2.

Answer:
50 mg.
Explanation:
From the prescription, 240 ml amount is to be prepared containing 30 ml tussin syrup. As the frequency is 5 mL qid, it means 5mL of syrup is to be administered four times daily i.e. 20 mL daily. To calculate the amount of tussin taken daily,
<em> </em><em><u>30 mL tussin</u></em><em> = </em><em><u>X mL of tussin</u></em>
<em> 240 mL solution 20ml solution</em>
⇒ 2.5 mL of tussin
5 ml tussin contains 100mg guafenesin,
So,
⇒ 2.5 ml of tussin contains 100x2.5/5 = 50 mg guaifenesin
1.50 atm(760 mmHg/1 atm)=1140 mmHg