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Diano4ka-milaya [45]
3 years ago
14

Calculate the volume in milliliters of a 1.27 mol/L silver perchlorate solution that contains 125.mmol of silver perchlorate (Ag

ClO4) . Round your answer to significant digits.
Chemistry
1 answer:
Lunna [17]3 years ago
7 0

Answer:

This solution has a volume of 98.4 mL

Explanation:

Step 1: Data given

Molarity of AgClO4 solution = 1.27 mol/L

Number of moles AgClO4 = 125 mmol = 0.125 mol

Molar mass of AgClO4= 207.32 g/mol

Step 2: Calculate volume of the 1.27 M solution

Molarity = moles / volume

Volume = moles / molarity

Volume = 0.125 moles / 1.27 mol /L

Volume = 0.0984 L = 98.4 mL

This solution has a volume of 98.4 mL

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DIA [1.3K]
  • V_1=49.8mL
  • T_1=18°C=291K
  • T_2=83°C=356K

Using Charles law

\\ \sf\longmapsto V_1T_2=V_2T_1

\\ \sf\longmapsto V_2=V_1T_2\div T_1

\\ \sf\longmapsto V_2=\dfrac{49.8(356)}{291}

\\ \sf\longmapsto V_2=\dfrac{17728.8}{291}

\\ \sf\longmapsto V_2=60.9mL

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