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Diano4ka-milaya [45]
3 years ago
14

Calculate the volume in milliliters of a 1.27 mol/L silver perchlorate solution that contains 125.mmol of silver perchlorate (Ag

ClO4) . Round your answer to significant digits.
Chemistry
1 answer:
Lunna [17]3 years ago
7 0

Answer:

This solution has a volume of 98.4 mL

Explanation:

Step 1: Data given

Molarity of AgClO4 solution = 1.27 mol/L

Number of moles AgClO4 = 125 mmol = 0.125 mol

Molar mass of AgClO4= 207.32 g/mol

Step 2: Calculate volume of the 1.27 M solution

Molarity = moles / volume

Volume = moles / molarity

Volume = 0.125 moles / 1.27 mol /L

Volume = 0.0984 L = 98.4 mL

This solution has a volume of 98.4 mL

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Answer: The mass is 980.6g of Gold.

Explanation:

We begin by looking for the number of moles equivalent to 3.0 x 10^24 gold atoms.

Using the Avogadro's number,

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3.0 x 10^24 atoms would make up: 1 / 6.02 x 10^23 x 3.0 x 10^24 = 4.98moles.

Now that we know the number of moles, we can then look for the mass using the formular:

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4.98 = mass / 196.9 (atomic mass of gold)

Making "mass" the subject of formula : mass = 4.98 x 196.9= 980.6g

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Answer:

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1 Kilometer   =   39370 inches

So, for your question we want to go 405,696 km....

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