Answer:
<em>O</em><em>r</em><em>g</em><em>a</em><em>n</em><em>i</em><em>s</em><em>m</em><em> </em><em>,</em><em> </em><em>P</em><em>o</em><em>p</em><em>u</em><em>l</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>,</em><em> </em><em>C</em><em>o</em><em>m</em><em>m</em><em>u</em><em>n</em><em>i</em><em>t</em><em>y</em><em> </em><em>,</em><em> </em><em>E</em><em>c</em><em>o</em><em>s</em><em>y</em><em>s</em><em>t</em><em>e</em><em>m</em><em> </em><em>.</em>
Explanation:
<u>Organism</u> is one type of species .
<u>Population</u> is a group of same species living together .
<u>Community</u> is a group of different species living together .
<u>Ecosystem</u> is a large group of community of species and its environment consisting of biotic and abiotic factor .
Answer:
Saturated solution = 180 gram
Explanation:
Given:
Solubility of Z = 60 g / 100 g water
Given temperature = 20°C
Amount of water = 300 grams
Find:
Saturated solution
Computation:
Saturated solution = [Solubility of Z] × Amount of water
Saturated solution = [60 g / 100 g] × 300 grams
Saturated solution = [0.6] × 300 grams
Saturated solution = 180 gram
Answer:
Answer is explained in the explanation section below.
Explanation:
Solution:
Note: This question is incomplete and lacks very important data to solve this question. But I have found the similar question which shows the profiles about which question discusses. Using the data from that question, I have solved the question.
a) We need to find the major species from A to F.
Major Species at A:
1. 
Major Species at B:
1. 
2. 
Major Species at C:
1. 
Major Species at D:
1. 
2. 
Major Species at E:
1. 
Major Species at F:
1. 
b) pH calculation:
At Halfway point B:
pH = pK
+ log[
]/[H
]
pH = pK
= 6.35
Similarly, at halfway point D.
At point D,
pH = pK
+ log [H
]/[H2
]
pH = pK
= 10.33
Answer:
carbon dioxide concentration goes down, temperature goes down. Carbon dioxide goes up temp goes up, carbon dioxide is directly related to temperature by insulating it in the earths atmosphere and if there's less of it then the temp would go down.
Explanation:
First, we convert the moles of each substance into the concentration using the volume of the reactor.
[SO₃] = 0.425/1.5 = 0.283 M
[SO₂] = 0.208 / 1.5 = 0.139 M
[O₂] = 0.208/1.5 = 0.139 M
The equilibrium constant is calculated by:
Kc = [SO₃]² / [O₂][SO₂]²
Kc = (0.283)²/(0.139)(0.139)²
Kc = 29.8 = 2.98 x 10¹
The answer is C