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Amanda [17]
3 years ago
10

So i have a science question i need help with: Explain why it is a good practice to leave a hot beaker to cool before washing un

der running tap water.
Chemistry
1 answer:
Ronch [10]3 years ago
6 0
If you do not let the pot cool, it could mold when it goes into the cold water, and end up dented
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Explain the difference between molecule and compound
nadya68 [22]
Answer:
A molecule is a group of two or more atoms held together by chemical bonds. A compound is a substance which is formed by two or more different types of elements which are united chemically in a fixed proportion. All molecules are not compounds.

Good luck !
8 0
2 years ago
Which of the following best describes the relationship of solar UV radiation to the environment?
aliya0001 [1]
<span> UV radiation are high energy radiations and they are mutation causing agents so
</span>Mutagen <span> best describes the relationship of solar UV radiation to the environment
so option A is correct
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4 0
3 years ago
Ammonia is produced by the following reaction. 3H2(g) N2(g) Right arrow. 2NH3(g) When 7. 00 g of hydrogen react with 70. 0 g of
harkovskaia [24]

In the ammonia production process given by the reaction 3H₂(g) + N₂(g) → 2NH₃(g), when 7.00 g of hydrogen react with 70.0 g of nitrogen, hydrogen is considered the limiting reactant because <u>7.5 moles of hydrogen would be needed to consume the available nitrogen</u> (option 1).

The reaction is the following:

3H₂(g) + N₂(g) → 2NH₃(g)   (1)

To know why hydrogen is considered the limiting reactant, we need to calculate the number of moles of nitrogen and hydrogen with the following equation:

n = \frac{m}{M}

Where:    

m: is the mass

M: is the molar mass

  • For <em>hydrogen </em>we have:

n_{H_{2}} = \frac{m}{M} = \frac{7.00 g}{2.016 g/mol} = 3.47 \:moles

  • And for <em>nitrogen</em>:

n_{N_{2}} = \frac{m}{M} = \frac{70.0 g}{28.013 g/mol} = 2.50 \:moles

We can see in reaction (1) that <u>3 moles of hydrogen</u> react with <u>1 mol of nitrogen</u>, so the number of hydrogen moles needed to react nitrogen is:

n_{H_{2}} = \frac{3\:moles\:H_{2}}{1\:moles\:N_{2}}*n_{N_{2}} = \frac{3\:moles\:H_{2}}{1\:moles\:N_{2}}*2.50 \:moles = 7.50 \:moles

Since we have <u>3.47 moles of hydrogen</u> and we need <u>7.50 moles</u> to react with all the mass of nitrogen, the <em>limiting reactant</em> is <em>hydrogen</em>.

We can find the number of ammonia moles produced with the limiting reactant (hydrogen) konwing that <u>3 moles of hydrogen</u> produces <u>2 moles of ammonia</u>, so:

n_{NH_{3}} = \frac{2\:moles\:NH_{3}}{3\:moles\:H_{2}}*n_{H_{2}} = \frac{2\:moles\:NH_{3}}{3\:moles\:H_{2}}*3.47 \:moles = 2.31 \:moles

Hence, hydrogen would produce <u>2.31 moles of ammonia</u>.

Therefore, hydrogen is the limiting reactant because <u>7.5 moles of hydrogen would be needed to consume the available nitrogen</u> (option 1).

Find more about limiting reactants here:

brainly.com/question/2948214?referrer=searchResults

   

I hope it helps you!                        

6 0
3 years ago
12 Ethene gas, CH is completely burned in excess oxygen to form carbon dioxide and water
Natali [406]

Answer:

12 Ethene gas, CH is completely burned in excess oxygen to form carbon dioxide and water

The equation for this exothermic reaction is shown.

CH 30, - 200, 2H,0

The table shows the bond energies involved in the reaction

bond

bond energy

(kJ/moly

614

413

C-C

CHH

0 0

СО

495

799

O-H

467

What is the total energy change in this reaction?

A-954 kJ/mol

B-1010 kJ/mol

C-1313 kJ/mol

D-1359 kJ/mol

Explanation:

thats all you said

5 0
3 years ago
The overall long-term effects of air pollution are not yet certain.<br><br> True<br> False
Viktor [21]
I’m pretty positive the answer is True
6 0
3 years ago
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