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2 years ago

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How can you predict an elements group and period

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mina [271]2 years ago

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What is the molarity of 0.540g Mg N,0. in 250 mL of solution?

Sati [7]

Answer:

2.16x10^-03

molarity=mass÷volume

0.540÷250

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2 years ago

Which of the following experiments would best test viscosity?

Juli2301 [7.4K]

C. pouring honey on a plate so the density of thickness and stickyness would
be the highest

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3 years ago

(Chemistry) Match each item with the correct statement below.

Colt1911 [192]

$Number\;1:\;Formula.\\\\Number\;2:\;Solution\\\\Number\;3:\;Chemistry\\\\Number\;4:\;Solute\\\\Number\;5:\;Mass\\\\Number\;6:\;Matter\\\\Number\;7:\;Alloy\\\\Number\;8:\;Aqueous\\\\Number\;9:\;Quantitative$

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2 years ago

A 50.0 mL sample of a 1.00 M solution of CuSO4 is mixed with 50.0 mL of 2.00 M KOH in a calorimeter. The temperature of both sol

Reika [66]

Answer : The enthalpy change for the process is 52.5 kJ/mole.

Explanation :

Heat released by the reaction = Heat absorbed by the calorimeter + Heat absorbed by the solution

$q=[q_1+q_2]$

$q=[c_1\times \Delta T+m_2\times c_2\times \Delta T]$

where,

q = heat released by the reaction

$q_1$ = heat absorbed by the calorimeter

$q_2$ = heat absorbed by the solution

$c_1$ = specific heat of calorimeter = $12.1J/^oC$

$c_2$ = specific heat of water = $4.18J/g^oC$

$m_2$ = mass of water or solution = $Density\times Volume=1/mL\times 100.0mL=100.0g$

$\Delta T$ = change in temperature = $T_2-T_1=(26.3-20.2)^oC=6.1^oC$

Now put all the given values in the above formula, we get:

$q=[(12.1J/^oC\times 6.1^oC)+(100.0g\times 4.18J/g^oC\times 6.1^oC)]$

$q=2623.61J$

Now we have to calculate the enthalpy change for the process.

$\Delta H=\frac{q}{n}$

where,

$\Delta H$ = enthalpy change = ?

q = heat released = 2626.61 J

n = number of moles of copper sulfate used = $Concentration\times Volume=1M\times 0.050L=0.050mole$

$\Delta H=\frac{2623.61J}{0.050mole}=52472.2J/mole=52.5kJ/mole$

Therefore, the enthalpy change for the process is 52.5 kJ/mole.

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3 years ago

A hot metal plate at 150°C has been placed in air at room temperature. Which event would most likely take place over the next fe

Oksi-84 [34.3K]

Answer:

d. The air molecules that are surrounding the metal will speed up, and the molecules in the metal will slow down.

Explanation:

hopes this helps

sorry if it doesn't

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8 0

2 years ago