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3 years ago

How would the consumption of antacid (sodium bicarbonate) affect urine pH?

1 answer:

7 0

The consumption of antacid affect urine pH by increasing the pH of urine. Sodium bicarbonate or antacid neutralizes the acidity in the stomach. It is expelled in the body through the urine by alkalizing it. Hope this answers the question.

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What two categories are used in classifying particulate matter?

Allushta [10]

The two categories for classifying particulate matter are through analysis of the intensive and extensive properties. Intensive properties are independent properties that can be measured independent of the amount of matter while extensive properties are measured dependent on the amount.

3 0

3 years ago

Hi i was wondering if you could subscribe to my youtub/e channel, you don't have to but it would mean the world to me, and stay

Inga [223]

Answer:

Explanation:

8 0

2 years ago

Read 2 more answers

Suppose that tugboat A exerts a force of 2000 Newton’s on the barge and tugboat B exerts a force of 4000 Newton’s in the opposit

Nimfa-mama [501]

2000N in the direction of tugboat B

Explanation:

Given parameters:

Force by tugboat A = 2000N

Force by tugboat B = 4000N

Unknown;

Net force on barge = ?

Solution:

The net force on the barge would be the resultant of the force on the barge.

Net force = Force on tugboat A - tugboat B

Net force = 2000N - 4000N = -2000N

The net force is directed towards the direction of the second barge i.e tugboat B of greater force.

learn more:

Newton brainly.com/question/11411375

#learnwithBrainly

5 0

3 years ago

Determine the energy of 1.70 mol of photons for each of the following kinds of light. (Assume three significant figures.)PART A

BabaBlast [244]

Answer:

For A: The energy of the given amount of photons for infrared radiation is $1.271\times 10^5J$

For B: The energy of the given amount of photons for infrared radiation is $4.026\times 10^5J$

For C: The energy of the given amount of photons for infrared radiation is $1.355\times 10^6J$

Explanation:

The relationship between energy and frequency is given by Planck's equation, which is:

$E=n\rimes N_A\times \frac{hc}{\lambda}$ ......(1)

where,

h = Planck's constant = $6.62\times 10^{-34}Js$

E = energy of the light

c = speed of light = $3\times 10^8m/s$

$\lambda$ = wavelength of light

$N_A$ = Avogadro's number = $6.022\times 10^{23}$

n = number of moles of photons = 1.70 moles

Conversion factor used: $1m=10^9nm$

For A:

Wavelength of infrared radiation = $1600nm=1.6\times 10^6m$

Putting values in equation 1, we get:

$E=1.7\times 6.022\times 10^{23}\times \frac{6.62\times 10^{-34}\times 3\times 10^8}{1.6\times 10^{-6}}\\\\E=1.271\times 10^5J$

Hence, the energy of the given amount of photons for infrared radiation is $1.271\times 10^5J$

For B:

Wavelength of visible light = $505nm=5.05\times 10^7m$

Putting values in equation 1, we get:

$E=1.7\times 6.022\times 10^{23}\times \frac{6.62\times 10^{-34}\times 3\times 10^8}{5.05\times 10^{-7}}\\\\E=4.026\times 10^5J$

Hence, the energy of the given amount of photons for infrared radiation is $4.026\times 10^5J$

For C:

Wavelength of ultraviolet radiation = $150nm=1.5\times 10^7m$

Putting values in equation 1, we get:

$E=1.7\times 6.022\times 10^{23}\times \frac{6.62\times 10^{-34}\times 3\times 10^8}{1.5\times 10^{-7}}\\\\E=1.355\times 10^6J$

Hence, the energy of the given amount of photons for infrared radiation is $1.355\times 10^6J$

3 0

3 years ago

When 16.4 g of steam at 100°C condenses how much heat is released?

OLEGan [10]

Answer:

37064 J

Explanation:

Data Given:

mass of Steam (m) = 16.4 g

heat released (Q) = ?

Solution:

This question is related to the latent heat of condensation.

Latent heat of condensation is the amount of heat released when water vapors condenses to liquid.

Formula used

Q = m x Lc . . . . . (1)

where

Lc = specific latent heat of condensation

Latent heat of vaporization of water is exactly equal to heat of condensation with - charge

So, Latent heat of vaporization of water have a constant value

Latent heat of vaporization of water = 2260 J/g

Latent heat of condensation of water will be = - 2260 J/g

Put values in eq. 1

Q = (16.4 g) x (- 2260 J/g)

Q = - 37064 J

So, 37064 J of heat will be released negative sign indicate release of energy

4 0

3 years ago