In the presence of heat, copper (II) hydroxide decomposes in to copper (II) oxide.
Cu(OH)₂ (s) ----> CuO (s) + H₂O (l)
upon decomposition, water is removed from Cu(OH)₂
the amount of Cu(OH)₂ decomposed - 3.67 g
number of moles of Cu(OH)₂ - 3.67 g / 97.5 g/mol = 0.038 mol
stoichiometry of Cu(OH)₂ to CuO is 1:1
therefore number of CuO moles formed are - 0.038 mol
CuO reacts with sulfuric acid to form CuSO₄
CuO + H₂SO₄ ---> CuSO₄ + H₂O
stoichiometry of CuO to H₂SO₄ is 1:1
therefore number of H₂SO₄ moles that should react is 0.038 mol
the molarity of H₂SO₄ is 3M
this means that in 1000 ml - 3 mol of H₂SO₄ present
so if 3 mol are present in 1000 ml
then volume for 0.038 mol = 1000/3 * 0.038
= 12.67 ml
Taking into account the definition of molarity, the molarity of solution of sodium sulfate is 0.0732
.
<h3>Definition of molarity</h3>
Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.
The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

Molarity is expressed in units
.
<h3>Molarity of solution of sodium sulfate.</h3>
In this case, you have:
- number of moles of sodium sulfate=
(being 142 g/mole the molar mass of sodiums sulfate) - volume= 500 mL= 0.5 L (being 1000 mL= 1 L)
Replacing in the definition of molarity:

Solving:
Molarity= 0.0732 
Finally, the molarity of solution of sodium sulfate is 0.0732
.
Learn more about molarity:
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Answer:
Moles of boron trifluoride gas that were collected = 11.6 mol
Mass of boron trifluoride gas that were collected = 787 g
Explanation:
Given that:
Temperature = 2.0 °C
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T = (2.0 + 273.15) K = 275.15 K
V = 15.0 L
Pressure = 0.130 atm
Using ideal gas equation as:
where,
P is the pressure
V is the volume
n is the number of moles
T is the temperature
R is Gas constant having value = 0.0821 L atm/ K mol
Applying the equation as:
0.130 atm × 15.0 L = n ×0.0821 L atm/ K mol × 275.15 K
⇒n = 11.6 mol
<u>Thus, Moles of boron trifluoride gas that were collected = 11.6 mol
</u>
Molar mass of boron trifluoride gas = 67.82 g/mol
The formula for the calculation of moles is shown below:
Thus,
<u>Mass of boron trifluoride gas that were collected = 787 g</u>
According to the <em>Law of Conservation of Mass</em>,
The mass of the products in a chemical reaction must equal the mass of the reactants.
∴ D is the Answer