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3 years ago

Convert the following to grams 0.500 moles of (NH4)2CO3

1 answer:

5 0

Molar mass (NH₄)₂CO₃ = <span>96.09 g/mol

1 mole ---------> 96.09 g
0.500 moles ----> ?

0.500 * 96.09 = 48.045 g of </span><span>(NH₄)₂CO₃

hope this helps!

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1 or 2 topics or two lessons should be explained in an illustrated childrens book minimum of 10 pages must have 3 or more senten

marysya [2.9K]

Answer:

Yes because same topic are long

8 0

3 years ago

According to the equation below, how many moles of PbO are required to generate 3.88×1023 nitrogen molecules?

saul85 [17]

Answer:

1.935 mole

Explanation:

We'll begin by calculating the number of mole present in 3.88x10^23 molecules of nitrogen(N2). This can be obtained as follow:

From Avogadro's hypothesis, 1 mole of any substance contains 6.02x10^23 molecules. Therefore 1 mole of N2 contains 6.02x10^23 molecules.

Now if 1 mole of N2 contains 6.02x10^23 molecules,

Then Xmol of N2 will contain 3.88x10^23 molecules i.e

Xmol of N2 = (3.88x10^23)/6.02x10^23

Xmol of N2 = 0.645 mole

Now, we can obtain the number of moles of PbO required to generate 3.88x10^23 molecules (i.e 0.645 mole) of N2. This is illustrated below:

The equation for the reaction is given below:

3PbO + 2NH3 → 3Pb + N2 + 3H2O

From the balanced equation above, 3 moles of PbO produced 1 mole of N2.

Therefore, Xmol of PbO will produce 0.645 mole of N2 i.e

Xmol of PbO = 3 x 0.645

Xmol of PbO = 1.935 mole.

From the calculations made above,

1.935 mole of PbO will produce 3.88x10^23 molecules of nitrogen (N2).

8 0

4 years ago

One of the steps in processing some metals is smelting. what does smelting do for a metal?

vichka [17]

Hey there,
Smelting's main use is to produce a base metal from its ore

Hope this helps :))

~Top

8 0

3 years ago

Convert 5.28 x 1019 molecules of C6H1206 to grams.

nlexa [21]

Answer:

$m=0.0158g$

Explanation:

Hello there!

In this case, it is possible to comprehend these mass-particles problems by means of the concept of mole, molar mass and the Avogadro's number because one mole of any substance has 6.022x10²³ particles and have a mass equal to the molar mass.

In such a way, for C₆H₁₂O₆, whose molar mass is about 180.16 g/mol, the referred mass would be:

$m=5.28x10^{19}molecules*\frac{1mol}{6.022x10^{23}molecules}*\frac{180.16g}{1mol}\\\\m=0.0158g$

Best regards!

5 0

3 years ago

What was the original pressure in a rigid container if the new pressure is 82.5atm and the temperature was raised from 44C to 67

zhenek [66]

Answer: 54 atm

Explanation:

I did 67/82.5 then got 0.8121212121. I them divided 44 by 0.81212121 and got 54.1791044776

4 0

3 years ago