Answer:
150J
Explanation:
work output/work input=100%
so just make work output the subject
Answer:
i think it Naturalistic observation
Explanation:
Complete Question:
The mass of the sphere is 0.151 kg. What is the rotational inertia of the wheel? Recall that the radius of the sphere is about 0.312 m. Express your answer with three significant figures in Kg.m².
Answer:
I = 5.88*10⁻³ kg.m²
Explanation:
It can be showed that the rotational inertia (or moment of inertia) for a solid sphere of radius r and mass m, regarding any axis passing through the center of the sphere, can be expressed as follows:
I = (2/5)*m*r² (1)
where m= 0.151 kg, and r =0.312 m. (Our givens).
Replacing in (1) we have:
I = (2/5)*0.151 kg*(0.312m)² = 5.88*10⁻³ kg.m²
Answer:
The force is 272.73 newtons
Explanation:
We're going to use impulse-momentum theorem that states impulse is the change on the linear momentum this is:
(1)
Impulse is also defined as average force times the time the force is applied:
(2)
By (2) on (1):

solving for
:
(3)
We already know Δt is equal to 0.22 s, all we should do now is to find
and put on (3) (
the initial momentum and
the final momentum). Linear momentum is defined as
, using that on (3):
(4)
Velocity (v) are vectors so direction matters, if positive direction is the right direction and negative direction left
and
so (4) becomes:

(5)
Using (5) on (3):


Answer:
F = 3.6 kN, direction is 9.6º to the North - East
Explanation:
The force is a vector, so one method to find the solution is to work with the components of the vector as scalars and then construct the resulting vector.
Let's use trigonometry to find the component of the forces, let's use a reference frame where the x-axis coincides with the East and the y-axis coincides with the North.
Wind
X axis
F₁ = 2.50 kN
Tide
cos 30 = F₂ₓ / F₂
sin 30 = F_{2y} / F₂
F₂ₓ = F₂ cos 30
F_{2y} = F₂ sin 30
F₂ₓ = 1.20cos 30 = 1.039 kN
F_{2y} = 1.20 sin 30 = 0.600 kN
the resultant force is
X axis
Fₓ = F₁ₓ + F₂ₓ
Fₓ = 2.50 +1.039
Fₓ = 3,539 kN
F_y = F_{2y}
F_y = 0.600
to find the vector we use the Pythagorean theorem
F = 
F = 
F = 3,589 kN
the address is
tan θ = F_y / Fₓ
θ = tan⁻¹
θ = tan⁻¹
0.6 / 3.539
θ = 9.6º
the resultant force to two significant figures is
F = 3.6 kN
the direction is 9.6º to the North - East