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yan [13]
3 years ago
9

A 100 mH inductor whose windings have a resistance of 6.0 Ω is connected across a 12 Vbattery having an internal resistance of 3

.0 Ω .How much energy is stored in the inductor?
Physics
1 answer:
Alexus [3.1K]3 years ago
7 0

Answer:

The store energy in the inductor is 0.088 J

Explanation:

Given that,

Inductor = 100 mH

Resistance = 6.0 Ω

Voltage = 12 V

Internal resistance = 3.0 Ω

We need to calculate the current

Using ohm's law

V = IR

I=\dfrac{V}{R+r}

Put the value into the formula

I=\dfrac{12}{6.0+3.0}

I=1.33\ A

We need to calculate the store energy in the inductor

U=\dfrac{1}{2}LI^2

U=\dfrac{1}{2}\times100\times10^{-3}\times(1.33)^2

U=0.088\ J

Hence, The store energy in the inductor is 0.088 J

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D is the diameter of the Sun

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D=\frac{d}{x_{sunball-pinhole}}x_{sun-pinhole}

D=\frac{17.91(10)^{-3}  m}{1.791 m} 1.5(10)^{11}  m

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