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1 year ago

Which material is more closely related to the styrofoam? a. heat exchanger b. diffuser c. insulator d. electrical conductor

Physics

1 answer:

nirvana33 [79]1 year ago

8 0

The material that is more closely related to the Styrofoam insulator.

Styrofoam is the term that is used for polystyrene foam in a trademark form. It is a petroleum-based plastic.

Keeping something warm includes the stopping of the transfer of heat from one object to another. This is how insulation works.

Styrofoam is an insulator, which means it'll help keep the heat from the environment out of your cooler. However, you'll still need cooling agents (like ice packs) to make the cooler cold in the first place.

Styrofoam is usually made mostly of air, which means it is a poor conductor of heat, but an excellent convector. It traps the air in small pockets, which blocks the flow of heat energy. This reduces both conduction and convection and makes Styrofoam a good insulator.

To learn more about Styrofoam here

brainly.com/question/21369568

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Which of the following microscope parts should routinely be adjusted to control the light source and provide optimal illuminatio

yKpoI14uk [10]

Here is the answer. The microscope parts that should routinely be adjusted to control the light source and provide optimal illumination of the specimen are the following: light source; condenser; specimen; objective lens; ocular lens. Hope this answers your question.

3 0

3 years ago

Some substances have the same chemical composition, but their atoms are arranged differently. A classic example is carbon. A pen

Bumek [7]

No, the density of diamond and graphite would not be the same

Explanation:

What is density?

Density is the amount of substance per unit volume. It is simply mass divided by volume.

Density is greatly influenced by the way substances are packed.

Substances that are well packed will have lower volume for the same amount of matter than another that is poorly packed.

The carbon atoms in graphite are poorly packed. They are arranged layers upon layers.
Diamond carbon atoms have a cross-linked networked pattern. They are well packed.
For the same mass of matter, graphite will take up more space than diamond.

Since:

Density = $\frac{mass}{volume}$

The one that has a lesser volume will have a higher density.

Therefore diamond will have a higher density.

learn more:

Density brainly.com/question/5055270

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4 0

2 years ago

Read 2 more answers

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Schach [20]

Answer:

Explanation:

7 0

2 years ago

Read 2 more answers

A 5 meter long ladder leans against a wall. The bottom of the ladder slides away from the wall at the constant rate of 1 3 m/s.

Oksana_A [137]

Answer:9.75 m/s

Explanation:

Given

Length of ladder $(L)=5 m$

Foot the ladder is moving away with speed of $\frac{\mathrm{d} x}{\mathrm{d} t}=13 m/s$

From diagram

$x^2+y^2=L^2$ ------1

at $x=3$

$y^2=25-9=16$

$y=4 m$

Now differentiating equation 1 w.r.t time

$2x\frac{\mathrm{d} x}{\mathrm{d} t}+2y\frac{\mathrm{d} y}{\mathrm{d} t}=0$

$x\frac{\mathrm{d} x}{\mathrm{d} t}=-y\frac{\mathrm{d} y}{\mathrm{d} t}$

$3\times 13=-4\times \frac{\mathrm{d} y}{\mathrm{d} t}$

$\frac{\mathrm{d} y}{\mathrm{d} t}=-\frac{3\times 13}{4}=-9.75 m/s$

negative indicates distance is decreasing with time

5 0

2 years ago

A subway train is traveling at 22.2 m/s when it approaches a slower train 50m ahead traveling in the same direction at 6.94 m/s.

Amiraneli [1.4K]

Answer:

Time that they collide = 4.99s

Relative speed of the trains when they collide: The relative speed of The first train relative to the second, slower train at collision = 4.781 m/s

Explanation:

We will use the equations of motion to obtain the solution required

At time t = 0

speed of first train = 22.2 m/s

Initial space between the two trains = 50 m

Speed of second train = 6.94 m/s

For the first car, distance covered by the first train = y

y = distance covered between the beginning of the deceleration and the point where the the two trains hit one another.

u = initial velocity = 22.2 m/s

t = time taken for all this to happen

a = deceleration = - 2.1 m/s²

y = ut + (1/2)at²

y = 22.2t - 1.05t² (eqn 1)

For the second train,

At t = 0, y = 50 m

Let the new distance moved by the second train before collision = (y - 50)

u = initial velocity = 6.94 m/s

t = time taken = t

a = acceleration of the second train = 0 m/s² (constant velocity)

(y - 50) = ut + (1/2)at²

y - 50 = 6.94t

y = 6.94t + 50 (eqn 2)

substituting for y in eqn 2 using the expression obtained in eqn 1

y = 22.2t - 1.05t²

y = 6.94t + 50

22.2t - 1.05t² = 6.94t + 50

1.05t² - 15.26t + 50 = 0

Solving this quadratic equation

t = 4.99 s or 9.54 s

The position of the two trains are the same at those two times, but the first time is when they hit each other.

t = 4.99 s

At 4.99 s, the the velocity of the first train

v = u + at

v = 22.2 + (-2.1×4.99) = 11.721 m/s in the same direction as the second train.

Relative velocity at this point will be

= 11.721 - 6.94 = 4.781 m/s

Relative speed of the trains when they collide: The relative speed of The first train relative to the second, slower train at collision = 4.781 m/s

Hope this Helps!!!

4 0

2 years ago