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pantera1 [17]
2 years ago
6

Which material is more closely related to the styrofoam? a. heat exchanger b. diffuser c. insulator d. electrical conductor

Physics
1 answer:
nirvana33 [79]2 years ago
8 0

The material that is more closely related to the Styrofoam insulator.

Styrofoam is the term that is used for polystyrene foam in a trademark form. It is a petroleum-based plastic.

Keeping something warm includes the stopping of the transfer of heat from one object to another. This is how insulation works.

Styrofoam is an insulator, which means it'll help keep the heat from the environment out of your cooler. However, you'll still need cooling agents (like ice packs) to make the cooler cold in the first place.

Styrofoam is usually made mostly of air, which means it is a poor conductor of heat, but an excellent convector. It traps the air in small pockets, which blocks the flow of heat energy. This reduces both conduction and convection and makes Styrofoam a good insulator.

To learn more about Styrofoam here

brainly.com/question/21369568

#SPJ4

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the ocean floor is, on average, 4267 m below sea level. What is the pressure in the atmosphere at this depth?
hichkok12 [17]
The pressure at the depth h in the ocean is given by (Stevin's law)
p= p_0 + \rho g h
where
p_0 = 1.0 \cdot 10^5 Pa is the atmospheric pressure
and \rho g h is the pressure exerted by the column of water of height h=4267 m, with \rho = 1000 kg/m^3 being the water density and g=9.81 m/s^2.
Substituting, we find
p=1.0 \cdot 10^5 Pa + (1000 kg/m^3)(9.81 m/s^2)(4267 m)=4.20 \cdot 10^7 Pa
We want to convert this into atmospheres: we know that 1 atm corresponds to the atmospheric pressure at sea level, so 1 atm=1.0\cdot 10^5 Pa, therefore we just need to divide by this number:
p= \frac{4.20 \cdot 10^7 Pa}{1.0 \cdot 10^5 Pa/atm} =420 atm
7 0
3 years ago
In an experiment, an object is released from rest from the top of a building. Its speed is measured as it reaches a point that i
NikAS [45]

Answer:

so the speed will increase by 1.44 times then the initial speed if the distance is increased to double

Explanation:

As we know that the air friction or resistance due to air is neglected then we can use the equation of kinematics here

v_f^2 - v_i^2 = 2 a d

since we released it from rest so we have

v_i = 0

so here we have

v_f = \sqrt{2gd}

now if the distance is double then we have

v_f' = \sqrt{2g(2d)}

now from above two equations we can say that

v_f' = \sqrt2 v_f

so the speed will increase by 1.44 times then the initial speed if the distance is increased to double

4 0
3 years ago
An 800 kHz radio signal is detected at a point 3.2 km distant from a transmitter tower. The electric field amplitude of the sign
hammer [34]

Answer:

1.07 nT

Explanation:

We know that E/B = c where E = electric field amplitude = 320 mV/m = 0.32 V/m, B = magnetic field amplitude and c = speed of light = 3 × 10⁸ m/s.

So, B = E/c

Substituting E and c into B, we have

B = E/c

= 0.32 V/m ÷ 3 × 10⁸ m/s

= 0.1067 × 10⁻⁸ T

= 1.067 × 10⁻⁹ T

= 1.067 nT

≅ 1.07 nT

3 0
3 years ago
The mass of the earth is 5.98 1024 kg, the mass of the moon is 7.36 1022 kg, and the distance between the centers of the earth a
Setler [38]

Answer:

 x_{cm} = 4.644 10⁶ m

Explanation:

The center of mass is given by the equation

         x_{cm} = 1 / M_{total}  ∑ x_{i}  m_{i}

Where M_{total} is the total masses of the system, x_{i} is the distance between the particles and m_{i} is the masses of each body

Let's apply this equation to our problem

        M = Me + m

        M = 5.98 10²⁴ + 7.36 10²²

        M = 605.36 10²² kg

Let's locate a reference system located in the center of the Earth

Let's calculate

       x_{cm} = 1 / 605.36 10²²   [Me 0 + 7.36 10²² 3.82 10⁸]

       x_{cm} = 4.644 10⁶ m

4 0
3 years ago
18. Compared to its weight on Earth, a 5 kg object on the moon will weigh A. the same amount. B. less. C. more.
s2008m [1.1K]

Answer:

B. less

Explanation:

acceleration due to gravity on Earth, g = 9.8 m/s²

acceleration due to gravity on Moon, g = 1.6 m/s²

Given mass of the object as, m = 5 kg

Weight of an object is given as, W = mg

                                                         

Weight of the object on Earth, W = 5 x 9.8 = 49 N

Weight of the object on Moon, W = 5 x 1.6 = 8 N

Therefore, the object weighs less on the moon compared to its weight on Earth.

The correct option is "B. less"

8 0
3 years ago
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