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garri49 [273]
3 years ago
10

ABCD is a rhombus. Find AB. Give answer as a fraction in simplest form.​

Mathematics
2 answers:
LuckyWell [14K]3 years ago
5 0

Answer:

The length of AB = 97/3 units

Step-by-step explanation:

  • The length of CD = 7x+2
  • The length of BC = 4x+15

We know that a rhombus is a quadrilateral whose four sides all have the same length.

Thus, the equation becomes

7x+2 = 4x+15

7x-4x = 15-2

3x = 13

x = 13/3

So, the length of CD = 7x+2 = 7(13/3)+2

                                               = 91/3 + 2

                                               =  97/3

And, the length of BC = 4x+15 = 4(13/3) + 15

                                                  = 97/3

  • We already know that a rhombus is a quadrilateral whose four sides all have the same length.

Thus, the length of AB = 97/3 units

         

mart [117]3 years ago
4 0

Answer: 97/3

>>>>> 97 over 3

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

So we have the expression:

12-[20-2(6^2\div3\times2^2)]

Recall the order of operations or PEMDAS:

P: Operations within parentheses must be done first. On a side note, do parentheses before brackets.

E: Within the parentheses, if exponents are present, do them before all other operations.

M/D: Multiplication and division next, whichever comes first.

A/S: Addition and subtraction next, whichever comes first.

(Note: This is how the order of operations is traditionally taught and how it was to me. If this is different for you, I do apologize. However, the answer should be the same.)

Thus, we should do the operations inside the parentheses first. Therefore:

12-[20-2(6^2\div3\times2^2)]

The parentheses is:

(6^2\div3\times2^2)

Square the 6 and the 4:

(36\div3\times4)

Do the operations from left to right. 36 divided by 3 is 12. 12 times 4 is 48:

(36\div3\times4)\\=(12\times4)\\=48

Therefore, the original equation is now:

12-[20-2(6^2\div3\times2^2)]\\=12- [20-2(48)]

Multiply with the brackets:

=12-[20-96]

Subtract with the brackets:

=12-[-76]

Two negatives make a positive. Add:

=12+76=88

Therefore:

12-[20-2(6^2\div3\times2^2)]=88

3 0
4 years ago
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