Answer: -5.6
Step-by-step explanation:
That is the centroid.
The point where the lines from each vertex of the triangle to the midpoints of the opposite sides intersect.
Answer:
The total surface area of all 6 prisms is 6336 in^2.
Step-by-step explanation:
Let's find the surface area of ONE prism and then multiply that result by 6 to obtain the final answer.
One prism:
The area of the two 13 in by 26 in rectangular tabs is 2(13 in)(26 in), or 676 in^2 (subtotal);
The area of the two triangles of base 10 in and height 12 in is 2([1/2][10 in][12 in], or 120 in^2; and, finally,
The area of the 10 in by 26 in base is 260 in^2.
The total surface area of ONE prism is thus:
676 in^2 + 120 in^2 + 260 in^2, or 1056 in^2.
Now, because there are 6 of these prisms, multiply this last result by 6:
6(1056 in^2) = 6336 in^2.
The total surface area of all 6 prisms is 6336 in^2.
It would be bisecting angles
<span>Find the exact value of sec(-4π/3). Note that one full rotation, clockwise, would be -2pi. We have to determine the Quadrant in which this angle -4pi/3 lies. Think of this as 4(-pi/3), or 4(-60 degrees). Starting at the positive x-axis and rotating clockwise, we reach -60, -120, -180 and -240 degrees. This is in Q III. The ray representing -240 has adj side = -1 and opp side = to sqrt(3).
Using the Pyth. Theorem to find the length of the hypo, we get hyp = 2.
Thus, the secant of this angle in QIII is hyp / adj, or 2 / sqrt(3) (answer). This could also be written as (2/3)sqrt(3).
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