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nadya68 [22]
3 years ago
10

Write the equation of the line through (6,4) that is parallel to the line whose equation is y= 1/2 x+7. Show all work below and

place it in Slope Intercept Form.
Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
5 0

Answer:

\displaystyle y = \frac{1}{2}x + 1

Step-by-step explanation:

4 = ½[6] + b

3

\displaystyle 1 = b \\ \\ y = \frac{1}{2}x + 1

I am joyous to assist you anytime.

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Sara bought a pair of shoes that were $64 but were on sale for $46. Sales tax is 6%. How much did she pay for the shoes?
babymother [125]

Answer:

$48.76

Step-by-step explanation:

So, Sara bought the pair of shoes for $46 due to a discount.

Sales tax was 6% or 0.06. In other words, she had to pay 0.06(46)=2.76 for tax.

Thus, the total amount Sara paid for the shoes is $46+$2.76=$48.76

8 0
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What would be the solution to the inequality? x-20<100
BlackZzzverrR [31]

Answer:

the answer would be anything between 0-119 because any of these numbers minus 20 is still less than 100

tell me if this helped

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3 years ago
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The table below shows the results of a random sample of 160 teenagers.          Like To Surf || Do not like to Surf || Totals
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The answer is A,C,D

I checked and that is the correct answers. 
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3 years ago
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Simplify and then classify by degree and number of terms<br> 2x+3x^2(4x-5)
Delicious77 [7]

Answer:

2x + 3x^2 (4x - 5)

2x + 12x^3 - 15x^2

12x^3 - 15x^2 + 2x

Degree - 3

Terms - 3 (Trinomial)

<h3>Lets explore more - </h3>

  • The degree of a polynomial is the highest power of its variable
  • Degree represents the no. of zeros of the polynomial

  • <em><u>Linear</u></em><em><u> </u></em> - Degree 1
  • <em><u>Quadrati</u></em><em><u>c</u></em><em><u> </u></em><em><u>-</u></em><em><u> </u></em>Degree 2
  • <em><u>Cubic</u></em><em><u> </u></em><em><u> </u></em><em><u>-</u></em><em><u> </u></em>Degree 3
  • <em><u>Biquadratic</u></em><em><u> </u></em><em><u> </u></em><em><u>-</u></em><em><u> </u></em>Degree 4

  • Terms - Classification of polynomial On the basis of terms

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  3. Trinomial - Polynomial which has 3 terms
5 0
3 years ago
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13 POINTS- please help me
allsm [11]

Answer:

See explanation

Step-by-step explanation:

16. Two parallel lines are cut by transversal. Angles with measures (6x+20)^{\circ} and (x+100)^{\circ} are alternate exterior angles. By alternate exterior angles, the measures of alternate exterior angles are the same:

6x+20=x+100\\ \\6x-x=100-20\\ \\5x=80\\ \\x=16

Then

(6x+20)^{\circ}=(6\cdot 16+20)^{\circ}=116^{\circ}\\ \\(x+100)^{\circ}=(16+100)^{\circ}=116^{\circ}

17. Two parallel lines are cut by transversal. Angles with measures (2x+12)^{\circ} and (3x-22)^{\circ} are alternate interior angles. By alternate interior angles, the measures of alternate interior angles are the same:

2x+12=3x-22\\ \\2x-3x=-22-12\\ \\-x=-34\\ \\x=34

Then

(2x+12)^{\circ}=(2\cdot 34+12)^{\circ}=80^{\circ}\\ \\(3x-22)^{\circ}=(3\cdot 34-22)^{\circ}=80^{\circ}

18. Two parallel lines are cut by transversal. Angles with measures (6x-7)^{\circ} and (5x+10)^{\circ} are alternate exterior angles. By alternate interior angles, the measures of alternate exterior angles are the same:

6x-7=5x+10\\ \\6x-5x=10+7\\ \\x=17

Then

(6x-7)^{\circ}=(6\cdot 17-7)^{\circ}=95^{\circ}\\ \\(5x+10)^{\circ}=(5\cdot 17+10)^{\circ}=95^{\circ}

19. The diagram shows two complementary angles with measures 2x^{\circ} and 56^{\circ}. The measures of complementary angles add up to 90^{\circ}, then

2x+56=90\\ \\2x=90-56\\ \\2x=34\\ \\x=17

Hence,

2x^{\circ}=2\cdot 17^{\circ}=34^{\circ}

Check:

34^{\circ}+56^{\circ}=90^{\circ}

20. Angles \angle 1 and \angle 2 are vertical angles. By vertical angles theorem, vertical angles are congruent, so

m\angle 1=m\angle 2\\ \\5x+7=3x+15\\ \\5x-3x=15-7\\ \\2x=8\\ \\x=4

Hence,

m\angle 1=(5x+7)^{\circ}=(5\cdot 4+7)^{\circ}=27^{\circ}\\ \\m\angle 2=(3x+15)^{\circ}=(3\cdot 4+15)^{\circ}=27^{\circ}

21. \angle 5 and \angle 8 are supplementary. The measures of supplementary angles add up to 180^{\circ}, so

m\angle 5+m\angle 8=180^{\circ}\\ \\3x-40+7x-120=180\\ \\10x-160=180\\ \\10x=180+160\\ \\10x=340\\ \\x=34

Therefore,

m\angle 5=(3x-40)^{\circ}=(3\cdot 34-40)^{\circ}=62^{\circ}\\ \\m\angle 8=(7x-120)^{\circ}=(7\cdot 34-120)^{\circ}=118^{\circ}\\ \\62^{\circ}+118^{\circ}=180^{\circ}

7 0
3 years ago
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