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Grace [21]
3 years ago
12

Its okay if you dont know it, i just need help

Mathematics
2 answers:
TEA [102]3 years ago
8 0

Answer:

6 gallons every minute. I hope this helped

Step-by-step explanation:

Rama09 [41]3 years ago
3 0

Answer:

A shower uses 6 gallons of water a minute

Step-by-step explanation:

We can find this out by dividing the gallons used, by the minutes

36/6=6

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3(2x - 1) + 7 = -44 solve for x
Jet001 [13]

Answer:

I love algebra anyways

The ans is in the picture with the  steps how i got it

(hope this helps can i plz have brainlist :D hehe)

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Find all numbers such that three times the number is greater than eight less than the number.
klio [65]

Answer:

ALL SUCH NUMBERS WHICH ARE GREATER THAN -4 satisfy the given condition.

Step-by-step explanation:

Here, assume such number = m

Now, given :

3 times the number = 3 x ( m) = 3 m

8 less than the given number =  m - 8

Now, according to the question:

3 times the number  > 8 less than the given number

or, 3 m > m - 8

or, 3m  - m > m - 8 + m

or, 2  m > - 8

or, m > - 4

Hence, all SUCH NUMBERS WHICH ARE GREATER THAN -4 satisfy the given condition.

6 0
3 years ago
Y-intercept = (0, 2)<br> slope = -3/7 what is the equation?
Marianna [84]

Answer:

y = -(3/7)x + 2

Step-by-step explanation:

(see attached)

recall that the slope-intercept form of a linear equation is

y = mx + b

where m = slope = given as -(3/7)

and b = y-intercept = 2

substituting these values into the eqation:

y = mx + b

y = -(3/7)x + 2

8 0
3 years ago
A large envelope is 0.085 cm thick. How thick would a stack of 100 of these envelopes be? Explain your reasoning.
Pavlova-9 [17]

Answer:

8.5 cm

Step-by-step explanation:

I think because wouldn't you take the 0.085 · 100

(get mad if I'm wrong i might be)

3 0
2 years ago
Find the differential coefficient of <br><img src="https://tex.z-dn.net/?f=e%5E%7B2x%7D%281%2BLnx%29" id="TexFormula1" title="e^
Gemiola [76]

Answer:

\rm \displaystyle y' =   2 {e}^{2x}   +    \frac{1}{x}  {e}^{2x}  + 2 \ln(x) {e}^{2x}

Step-by-step explanation:

we would like to figure out the differential coefficient of e^{2x}(1+\ln(x))

remember that,

the differential coefficient of a function y is what is now called its derivative y', therefore let,

\displaystyle y =  {e}^{2x}  \cdot (1 +   \ln(x) )

to do so distribute:

\displaystyle y =  {e}^{2x}  +   \ln(x)  \cdot  {e}^{2x}

take derivative in both sides which yields:

\displaystyle y' =  \frac{d}{dx} ( {e}^{2x}  +   \ln(x)  \cdot  {e}^{2x} )

by sum derivation rule we acquire:

\rm \displaystyle y' =  \frac{d}{dx}  {e}^{2x}  +  \frac{d}{dx}   \ln(x)  \cdot  {e}^{2x}

Part-A: differentiating $e^{2x}$

\displaystyle \frac{d}{dx}  {e}^{2x}

the rule of composite function derivation is given by:

\rm\displaystyle  \frac{d}{dx} f(g(x)) =  \frac{d}{dg} f(g(x)) \times  \frac{d}{dx} g(x)

so let g(x) [2x] be u and transform it:

\displaystyle \frac{d}{du}  {e}^{u}  \cdot \frac{d}{dx} 2x

differentiate:

\displaystyle   {e}^{u}  \cdot 2

substitute back:

\displaystyle    \boxed{2{e}^{2x}  }

Part-B: differentiating ln(x)•e^2x

Product rule of differentiating is given by:

\displaystyle  \frac{d}{dx} f(x) \cdot g(x) = f'(x)g(x) + f(x)g'(x)

let

  • f(x) \implies   \ln(x)
  • g(x) \implies    {e}^{2x}

substitute

\rm\displaystyle  \frac{d}{dx}  \ln(x)  \cdot  {e}^{2x}  =  \frac{d}{dx}( \ln(x) ) {e}^{2x}  +  \ln(x) \frac{d}{dx}  {e}^{2x}

differentiate:

\rm\displaystyle  \frac{d}{dx}  \ln(x)  \cdot  {e}^{2x}  =   \boxed{\frac{1}{x} {e}^{2x}  +  2\ln(x)  {e}^{2x} }

Final part:

substitute what we got:

\rm \displaystyle y' =   \boxed{2 {e}^{2x}   +    \frac{1}{x}  {e}^{2x}  + 2 \ln(x) {e}^{2x} }

and we're done!

6 0
3 years ago
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