5 × 12 = 60 I got 60mph I multiply and that's how I get 60
A unit of measurement expressing the intensity of a sound of power of an electrical sound
Answer:
C-D
Explanation:
As you can see from the graph, the distance from A to B was from 0 m to 6 m in a duration of 3 seconds.
Divide 6 meters by 3 seconds to find the speed:
6 ÷ 3 = 2 m/s
B-C is not moving due to a straight line as said in the graph, so speed is
0 m/s.
There is also C-D since the car traveled from a distance of 9 meters
(6 -(-3) = 9) in 3 seconds too. (NOTE: The graph line going down does not mean it is slowing down, but rather going to a certain distance like going backwards)
Divide 9 meters by 3 seconds to get the speed:
9 ÷ 3 = 3 m/s
Between A-B, B-C, and C-D, C-D has the fastest speed recorded with 3 m/s.
A-D does not count here as the line has no connection between point A and point D.
Cheers!
Answer:
The time is
The speed is
Explanation:
From the question we are told that
The height of the cliff is
Generally from kinematic equation we have that
before the jump the persons initial velocity is u = 0 m/s
So
=>
Generally from kinematic equation
=>
=>
In order to answer these questions, we need to know the charges on
the electron and proton, and then we need to know the electron's mass.
I'm beginning to get the creepy feeling that, in return for the generous
5 points, you also want me to go and look these up so I can use them
in calculations ... go and collect my own straw to make the bricks with,
as it were.
Ok, Rameses:
Elementary charge . . . . . 1.6 x 10⁻¹⁹ coulomb
negative on the electron
plussitive on the proton
Electron rest-mass . . . . . 9.11 x 10⁻³¹ kg
a). The force between two charges is
F = (9 x 10⁹) Q₁ Q₂ / R²
= (9 x 10⁹ m/farad) (-1.6 x 10⁻¹⁹C) (1.6 x 10⁻¹⁹C) / (5.35 x 10⁻¹¹m)²
= ( -2.304 x 10⁻²⁸) / (5.35 x 10⁻¹¹)²
= 8.05 x 10⁻⁸ Newton .
b). Centripetal acceleration =
v² / r .
A = (2.03 x 10⁶)² / (5.35 x 10⁻¹¹)
= 7.7 x 10²² m/s² .
That's an enormous acceleration ... about 7.85 x 10²¹ G's !
More than enough to cause the poor electron to lose its lunch.
It would be so easy to check this work of mine ...
First I calculated the force, then I calculated the centripetal acceleration.
I didn't use either answer to find the other one, and I didn't use " F = MA "
either.
I could just take the ' F ' that I found, and the 'A' that I found, and the
electron mass that I looked up, and mash the numbers together to see
whether F = M A .
I'm going to leave that step for you. Good luck !