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tangare [24]
3 years ago
9

A dentist’s drill starts from rest. After 1.46 sof constant angular acceleration, it turns at arate of 27000 rev/min.Find the dr

ill’s angular acceleration.Answer in units of rad/s2.
Physics
1 answer:
Black_prince [1.1K]3 years ago
4 0

Answer:

616.3 rad/s²

Explanation:

Given that

t= 1.46 s

Initial angular velocity ,ωi = 0 rad/s

Final angular velocity ωf= 27000 rev/min

Angular speed in the rad/s given as

\omega_f=\dfrac{2\pi N}{60}\ rad/s

Now by putting the values

\omega_f=\dfrac{2\times 27000}{60}\ rad/s

ωf=900 rad/s

We know that (if acceleration is constant)

ωf=ωi + α t

α=Angular acceleration

900 = 0 + α x 1.46

\alpha=\dfrac{900}{1.46}\ rad/s^2\\\alpha=616.43\ rad/s^2

Therefore the acceleration will be 616.3 rad/s²  

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