Question

A simple pendulum consists of a small object of mass 1.70 kg hanging at the end of a 2.50 m long light string that is connected to a pivot point. (a) Calculate the magnitude of the torque (due to the force of gravity) about this pivot point when the string makes a 5.00° angle with the vertical.

Answer 1

Answer:  3.63 Nm

Explanation:

from the question we were given the following

mass = 1.7 kg

length of the string (r) = 2.5 ,m

angle θ = 5 degrees

acceleration due to gravity (g) = 9.8 m/s

we can calculate the torque using the formula Torques = m x g x r x sin θ

torque = 1.7 x 9.8 x 2.5 x sin 5

torque = 3.63 Nm