Please help me......................................

you run a delivery service between two small islands which are connected by a bridge and connected to the mainland by several br

ANEK [815]

Answer:

"Through" (and any subsequent words) was ignored because we limit queries to 32 words.

6 0

2 years ago

I need help please be quick

Valentin [98]

Answer:

angle A = 16°
angle B = 82°
angle C = 82°

i hope it helped ...

Step-by-step explanation:

see attached image for explanation.....

3 0

3 years ago

The price of a gallon of milk follows a normal distribution with a mean of $3.20 and a standard deviation of $0.10. What proport

Inga [223]

Answer:

$P(x$

Step-by-step explanation:

Mean $\=x=\$3.20$

Standard deviation $\sigma =\$0.10$

Estimated price $y=\$3.12$

Generally the equation for P(x<3.12) is mathematically given by

$P(x$

Since from Z table

$P(x$

Therefore the proportion of the milk vendors that have prices that were less than $3.12 per gallon is

$P(x$

6 0

3 years ago

points C,D, and E are collinear on CE, and CD:DE = 3/5. C is located at (1,8), D is located at (4,5), and E is located at (x,y).

kap26 [50]

Answer:

The point E is located at (9,0)

x=9, y=0

Step-by-step explanation:

we have that

Points C,D, and E are collinear on CE

Point D is between point C and point E

we know that

$CE=CD+DE$ -----> equation A (by addition segment postulate)

$\frac{CD}{DE}=\frac{3}{5}$

$CD=\frac{3}{5}DE$ ------> equation B

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Find the distance CD 

we have

C(1,8), D(4,5)

substitute in the formula

$CD=\sqrt{(5-8)^{2}+(4-1)^{2}}$

$CD=\sqrt{(-3)^{2}+(3)^{2}}$

$CD=\sqrt{18}\ units$

Find the distance DE

substitute the value of CD in the equation B and solve for DE

$\sqrt{18}=\frac{3}{5}DE$

$DE=\frac{5\sqrt{18}}{3}\ units$

Find the distance CE

$CE=CD+DE$

we have

$DE=\frac{5\sqrt{18}}{3}\ units$

$CD=\sqrt{18}\ units$

substitute the values in the equation A

$CE=\sqrt{18}+\frac{5\sqrt{18}}{3}$

$CE=\frac{8\sqrt{18}}{3}$

Applying the formula of distance CE

we have

$CE=\frac{8\sqrt{18}}{3}$

C(1,8), E(x,y)

substitute in the formula of distance

$\frac{8\sqrt{18}}{3}=\sqrt{(y-8)^{2}+(x-1)^{2}}$

squared both sides

$128=(y-8)^{2}+(x-1)^{2}$ -----> equation C

Applying the formula of distance DE

we have

$DE=\frac{5\sqrt{18}}{3}\ units$

D(4,5), E(x,y)

substitute in the formula of distance

$\frac{5\sqrt{18}}{3}=\sqrt{(y-5)^{2}+(x-4)^{2}}$

squared both sides

$50=(y-5)^{2}+(x-4)^{2}$ -----> equation D

we have the system

$128=(y-8)^{2}+(x-1)^{2}$ -----> equation C

$50=(y-5)^{2}+(x-4)^{2}$ -----> equation D

Solve the system by graphing

The intersection point both graphs is the solution of the system

The solution is the point (9,0)

therefore

The point E is located at (9,0)

see the attached figure to better understand the problem

6 0

3 years ago

Ryan can paint a fence in ten hours. Asanji

kumpel [21]

Answer:9

Step-by-step explanation:

I looked up the average and it said 9.

Good luck on the rest of quarantine homework! :D

Mark brainliest if u want. ONLY if u want :D

5 0

4 years ago