Question

Need help please assist me find the area of a regular hexagon

Answer 1

Answer:

The area of the regular hexagon is $166.3\ units^{2}$

Step-by-step explanation:

we know that

The area of a regular hexagon can be divided into 6 equilateral triangles

so

step 1

Find the area of one equilateral triangle

$A=\frac{1}{2}(b)(h)$

we have

$b=r=8\ units$

$h=4\sqrt{3}\ units$ ----> is the apothem

substitute

$A=\frac{1}{2}(8)(4\sqrt{3})$

$A=16\sqrt{3}\ units^{2}$

step 2

Find the area of 6 equilateral triangles

$A=(6)16\sqrt{3}=96\sqrt{3}=166.3\ units^{2}$