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hichkok12 [17]
3 years ago
6

Help this is due tommorow!!I just need to find quadrant 1 and 3 for that set of numbers! ​

Mathematics
1 answer:
Sidana [21]3 years ago
4 0

Answer:

Mathematics at Louisiana State University for their support in the ... Lesson 1: Positive and Negative Numbers on the Number Line—Opposite ... from Grade 5 of plotting points in the first quadrant and transition to locating ... Find and position integers and other rational numbers on a horizontal or ... tomorrow's water level.

Step-by-step explanation:

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Can anyone help my little sister with her math test please she gotta have it submitted by midnight tonight which is in like 2 ho
lesya [120]

Answer:

A. 17

Step-by-step explanation:

As you take 1/8 + 1/6 = 7/24

then you can see its 7 over 24

hence you take 24 - 7 =17

8 0
3 years ago
ALGREBRA - 4 PARTS
xenn [34]

Answer:

Estimate of population 0.61

(b) Margin of error = 0.07 The real population interval estimation is ± 7%.

c). Margin of error = 0.15

d) The real population's interval estimation is ± 15%

e). Yes, the action argument of the group is based on a half-range estimation of the true population. The reason that 62% ± 15% = 47%, or 77%, while 47% is similar to 45%, as the Collective action group states.

6 0
3 years ago
Angle CMW and angle WML together form angle CML. Angle CMW is a right angle. What must be true about angle CML?
ANTONII [103]
CML must be an obtuse angle.

Since CMW and WML together form CML, and CMW is a right angle, then CML must be larger than a right angle, which makes it obtuse.
3 0
3 years ago
Geometry question for homework.
mars1129 [50]

So remember that the distance formula is \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} .

1.

\sqrt{(4-4)^2+(-2-(-5))^2}\\ \sqrt{0^2+3^2}\\ \sqrt{0+9}\\ \sqrt{9}\\ 3

Distance between (4,-5) and (4,-2) is 3 units.

2.

\sqrt{(1-(-1))^2+(1-4)^2}\\ \sqrt{2^2+(-3)^2}\\ \sqrt{4+9}\\ \sqrt{13}

Distance between (1,1) and (-1,4) is √13 (or 3.61 rounded to the hundreths) units.

3 0
3 years ago
Perform the indicated matrix row operation and write the new matrix
Ne4ueva [31]
The given operation involves just swapping the two rows, so carrying out R_1\leftrightarrow R_2 on the matrix gives

\left[\begin{array}{cc|c}5&5&5\\1&-\dfrac23&5\end{array}\right]\to\left[\begin{array}{cc|c}1&-\dfrac23&5\\5&5&5\end{array}\right]
5 0
3 years ago
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